(a-1)x^2+(b+3)x+c=0

Lösung

(a - 1) x^{2} + (b + 3) x + c = 0

x = \frac{- b - 3 + ( b + 3 ) ^{2} - 4 c ( a - 1 )}{2 ( a - 1 )}, x = \frac{- b - 3 - ( b + 3 ) ^{2} - 4 c ( a - 1 )}{2 ( a - 1 )}; a \neq = 1

Schritte zur Lösung

(a - 1) x^{2} + (b + 3) x + c = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- ( b + 3 ) \pm ( b + 3 ) ^{2} - 4 ( a - 1 ) c}{2 ( a - 1 )}

x = \frac{- ( b + 3 ) + ( b + 3 ) ^{2} - 4 ( a - 1 ) c}{2 ( a - 1 )} : \frac{- b - 3 + ( b + 3 ) ^{2} - 4 c ( a - 1 )}{2 ( a - 1 )}

x = \frac{- ( b + 3 ) - ( b + 3 ) ^{2} - 4 ( a - 1 ) c}{2 ( a - 1 )} : \frac{- b - 3 - ( b + 3 ) ^{2} - 4 c ( a - 1 )}{2 ( a - 1 )}

Die Lösungen für die quadratische Gleichung sind:

x = \frac{- b - 3 + ( b + 3 ) ^{2} - 4 c ( a - 1 )}{2 ( a - 1 )}, x = \frac{- b - 3 - ( b + 3 ) ^{2} - 4 c ( a - 1 )}{2 ( a - 1 )}; a \neq = 1

\frac{1}{2} x^{2} + x - 1 = 0

- x^{2} - 1 - 2 x^{2} = 0

(3 x - 4)^{2} + (2 x - 3) (x + 5) = - (x^{2} + x + 3)

(3 - x) (- 3 - x) + 10 = 0

12 x^{2} + 48 x + 45 = 0