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Frequently Asked Questions (FAQ)
What are the solutions to the equation (3x-2)^2=(2x+3)(2x-3)+3(x+1) ?
- The solutions to the equation (3x-2)^2=(2x+3)(2x-3)+3(x+1) are x=2,x=1
Find the zeros of (3x-2)^2=(2x+3)(2x-3)+3(x+1)
- The zeros of (3x-2)^2=(2x+3)(2x-3)+3(x+1) are x=2,x=1