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人気のある代数 >

solvefor k,b(kd)((kd)/2)=nA(d-kd)

解

解く

k, b (k d) (\frac{k d}{2}) = n A (d - k d)

解

k = \frac{- n A + n A ( n A + 2 b d )}{b d}, k = - \frac{n A + n A ( n A + 2 b d )}{b d}; \frac{b d ^{2}}{2} \neq = 0

解答ステップ

b (k d) (\frac{k d}{2}) = n A (d - k d)

拡張

b (k d) (\frac{k d}{2}) : \frac{k ^{2} b d ^{2}}{2}

拡張

n A (d - k d) : n d A - kn d A

\frac{k ^{2} b d ^{2}}{2} = n d A - kn d A

kn d A

を左側に移動します

\frac{k ^{2} b d ^{2}}{2} + kn d A = n d A

n d A

を左側に移動します

\frac{k ^{2} b d ^{2}}{2} + kn d A - n d A = 0

標準的な形式で書く

a x^{2} + b x + c = 0

\frac{b d ^{2} k ^{2}}{2} + n d A k - n d A = 0

解くとthe二次式

k_{1, 2} = \frac{- n d A \pm ( n d A ) ^{2} - 4 \cdot \frac{b d ^{2}}{2} ( - n d A )}{2 \cdot \frac{b d ^{2}}{2}}

簡素化

(n d A)^{2} - 4 \cdot \frac{b d ^{2}}{2} (- n d A) : d n A (n A + 2 b d)

k_{1, 2} = \frac{- n d A \pm d n A ( n A + 2 b d )}{2 \cdot \frac{b d ^{2}}{2}}; \frac{b d ^{2}}{2} \neq = 0

解を分離する

k_{1} = \frac{- n d A + d n A ( n A + 2 b d )}{2 \cdot \frac{b d ^{2}}{2}}, k_{2} = \frac{- n d A - d n A ( n A + 2 b d )}{2 \cdot \frac{b d ^{2}}{2}}

k = \frac{- n d A + d n A ( n A + 2 b d )}{2 \frac{b d ^{2}}{2}} : \frac{- n A + n A ( n A + 2 b d )}{b d}

k = \frac{- n d A - d n A ( n A + 2 b d )}{2 \frac{b d ^{2}}{2}} : - \frac{n A + n A ( n A + 2 b d )}{b d}

二次equationの解:

k = \frac{- n A + n A ( n A + 2 b d )}{b d}, k = - \frac{n A + n A ( n A + 2 b d )}{b d}; \frac{b d ^{2}}{2} \neq = 0

グラフ

人気の例

x^{2} + 6 x + 19 = - 6

(m - 10)^{2} = - 20 m

0=-4/9 (x+2)^2+2

0 = - \frac{4}{9} (x + 2)^{2} + 2

q^2+8q+20=100-4q-q^2

q^{2} + 8 q + 20 = 100 - 4 q - q^{2}

3 x^{2} + 3 x = 18