ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある代数 >

(2x-1)^2-(x+1)^2=9

解

(2 x - 1)^{2} - (x + 1)^{2} = 9

解

x = 3, x = - 1

解答ステップ

(2 x - 1)^{2} - (x + 1)^{2} = 9

拡張

(2 x - 1)^{2} - (x + 1)^{2} : 3 x^{2} - 6 x

3 x^{2} - 6 x = 9

9

を左側に移動します

3 x^{2} - 6 x - 9 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 9) = 12

x_{1, 2} = \frac{- ( - 6 ) \pm 12}{2 \cdot 3}

解を分離する

x_{1} = \frac{- ( - 6 ) + 12}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 12}{2 \cdot 3}

x = \frac{- ( - 6 ) + 12}{2 \cdot 3} : 3

x = \frac{- ( - 6 ) - 12}{2 \cdot 3} : - 1

二次equationの解:

x = 3, x = - 1

グラフ

人気の例

2 a^{2} = a + 1

5 x^{2} - 23 x + 12 = 0

(x-2)(x+7)=-1+2x

(x - 2) (x + 7) = - 1 + 2 x

(x + n)^{2} + 4 = n^{2}

(x^2}{15}-\frac{2x-5)/3 = 4/5

\frac{x ^{2}}{15} - \frac{2 x - 5}{3} = \frac{4}{5}