簡約 2.12-(0.0592)/2*log_{10}((0.4)/(0.6))

解

簡約

2.12 - \frac{0.0592}{2} \cdot lo g_{10} (\frac{0.4}{0.6})

\frac{53}{25} - \frac{37}{1250} lo g_{10} (2) + \frac{37}{1250} lo g_{10} (3)

十進法表記

2.12521 \dots

解答ステップ

2.12 - \frac{0.0592}{2} lo g_{10} (\frac{0.4}{0.6})

2.12 = \frac{53}{25}

= \frac{53}{25} - \frac{0.0592}{2} lo g_{10} (\frac{0.4}{0.6})

\frac{0.0592}{2} = \frac{592}{20000}

= \frac{53}{25} - \frac{592}{20000} lo g_{10} (\frac{0.4}{0.6})

\frac{592}{20000} lo g_{10} (\frac{0.4}{0.6}) = \frac{37}{1250} (lo g_{10} (2) - lo g_{10} (3))

= \frac{53}{25} - \frac{37}{1250} (lo g_{10} (2) - lo g_{10} (3))

拡張

- \frac{37}{1250} (lo g_{10} (2) - lo g_{10} (3)) : - \frac{37}{1250} lo g_{10} (2) + \frac{37}{1250} lo g_{10} (3)

= \frac{53}{25} - \frac{37}{1250} lo g_{10} (2) + \frac{37}{1250} lo g_{10} (3)