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Frequently Asked Questions (FAQ)
What are the solutions to the equation 4x^2+76=32 ?
- The solutions to the equation 4x^2+76=32 are x=sqrt(11)i,x=-sqrt(11)i
Find the zeros of 4x^2+76=32
- The zeros of 4x^2+76=32 are x=sqrt(11)i,x=-sqrt(11)i