What are the solutions to the equation 4x^2+76=32 ?

The solutions to the equation 4x^2+76=32 are x=sqrt(11)i,x=-sqrt(11)i

Find the zeros of 4x^2+76=32

The zeros of 4x^2+76=32 are x=sqrt(11)i,x=-sqrt(11)i

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4 x^{2} + 76 = 32

x = 11 i, x = - 11 i

Solution steps

4 x^{2} + 76 = 32

Move

76

to the right side

4 x^{2} = - 44

Divide both sides by

4

x^{2} = - 11

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 11, x = - - 11

- 11 = 11 i

- - 11 = - 11 i

x = 11 i, x = - 11 i

\frac{1.1899 5 ^{2}}{2 \cdot 9.81}

- 16 t^{2} + 76 t - 88

0.1 t - 3 = 5

lo g_{\frac{1}{3}} (2 x) < 2 - lo g_{\frac{1}{3}} (\frac{1 - x}{x})

7 z^{2} + 8 z + 3 = 3 z^{2}

What are the solutions to the equation 4x^2+76=32 ?
The solutions to the equation 4x^2+76=32 are x=sqrt(11)i,x=-sqrt(11)i
Find the zeros of 4x^2+76=32
The zeros of 4x^2+76=32 are x=sqrt(11)i,x=-sqrt(11)i