What is (a^2+7a+10)/(a^2+2a-15)+(10)/(a-3) ?

The solution to (a^2+7a+10)/(a^2+2a-15)+(10)/(a-3) is (a+12)/(a-3)

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simplify (a^2+7a+10)/(a^2+2a-15)+(10)/(a-3)

simplify

\frac{a ^{2} + 7 a + 10}{a ^{2} + 2 a - 15} + \frac{10}{a - 3}

\frac{a + 12}{a - 3}

Solution steps

\frac{a ^{2} + 7 a + 10}{a ^{2} + 2 a - 15} + \frac{10}{a - 3}

Cancel

\frac{a ^{2} + 7 a + 10}{a ^{2} + 2 a - 15} : \frac{a + 2}{a - 3}

= \frac{a + 2}{a - 3} + \frac{10}{a - 3}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{a + 2 + 10}{a - 3}

Add the numbers:

2 + 10 = 12

= \frac{a + 12}{a - 3}

75 r^{2} - 27

1 3^{2} + 1 9^{2} = x^{2}

2 x - 6 = 4

∣ 3 x + 3 ∣ - 9 = - 2

\frac{4 c}{c + 3} - \frac{2}{c - 1}

What is (a^2+7a+10)/(a^2+2a-15)+(10)/(a-3) ?
The solution to (a^2+7a+10)/(a^2+2a-15)+(10)/(a-3) is (a+12)/(a-3)