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Frequently Asked Questions (FAQ)
What are the solutions to the equation k^2-k-8=0 ?
- The solutions to the equation k^2-k-8=0 are k=(1+sqrt(33))/2 ,k=(1-sqrt(33))/2
Find the zeros of k^2-k-8=0
- The zeros of k^2-k-8=0 are k=(1+sqrt(33))/2 ,k=(1-sqrt(33))/2