3x^2+16x-12<0

Lösung

3 x^{2} + 16 x - 12 < 0

- 6 < x < \frac{2}{3}

Intervall-Notation

(- 6, \frac{2}{3})

Dezimale

- 6 < x < 0.66666 \dots

Schritte zur Lösung

3 x^{2} + 16 x - 12 < 0

Faktorisiere

3 x^{2} + 16 x - 12 : (3 x - 2) (x + 6)

(3 x - 2) (x + 6) < 0

Identifiziere die Intervalle

- 6 < x < \frac{2}{3}

z^{2} + 3 z - 40 = 0

x^{2} - 9 = - 15

\frac{5 t}{6} - \frac{1}{3} = t - \frac{3}{2}

12 x^{2} - 18 = 0

x + 4 = 11