erweitern (3z+Δz)^2

Lösung

erweitern

(3 z + Δ z)^{2}

9 z^{2} + 6Δ z^{2} + Δ^{2} z^{2}

Schritte zur Lösung

(3 z + Δ z)^{2}

Wende Formel für perfekte quadratische Gleichungen an:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = 3 z, b = Δ z

= (3 z)^{2} + 2 \cdot 3 z Δ z + (Δ z)^{2}

Vereinfache

(3 z)^{2} + 2 \cdot 3 z Δ z + (Δ z)^{2} : 9 z^{2} + 6Δ z^{2} + Δ^{2} z^{2}

= 9 z^{2} + 6Δ z^{2} + Δ^{2} z^{2}

e x p an d \frac{u ( 1 + 7 s ) - s ^{3}}{s ^{2} ( s ^{2} + 4 )}

\frac{d ^{2}}{d x ^{2}} ((y) (\frac{9 x ^{4}}{4} - x + 3 e^{x}))

e x p an d \frac{1}{( x - a ) ^{3}} - \frac{1}{( x + a ) ^{3}}

e x p an d \frac{( 400 - x ) ^{2}}{100}

e x p an d x^{x^{x}} (x^{x} ln (x) (ln (x) + 1) + (x^{x - 1}))