展开 (e^t+e^{-t})^2t

解答

展开

(e^{t} + e^{- t})^{2} t

e^{2 t} t + 2 t + e^{- 2 t} t

求解步骤

(e^{t} + e^{- t})^{2} t

(e^{t} + e^{- t})^{2} = e^{2 t} + 2 + e^{- 2 t}

= t (e^{2 t} + e^{- 2 t} + 2)

= t (e^{2 t} + 2 + e^{- 2 t})

打开括号

= t e^{2 t} + t \cdot 2 + t e^{- 2 t}

= e^{2 t} t + 2 t + e^{- 2 t} t

e x p an d x^{2} + (y + 4)^{2} + x^{2} + (y - 4)^{2}

e x p an d (b ee)^{3} + b ee + 1

e x p an d \frac{3 x + 5}{( x - 3 ) ( x + 4 )}

e x p an d \frac{( x + 1 ) ^{4}}{( x - 1 ) \cdot ( x - 2 )}

e x p an d \frac{\frac{d}{d x} ( z ^{2} )}{( z + i ) ^{2}}