展开 (2x^3+(-5-2i)x^2+(1+i)x+(2+i))/(2+i)

解答

展开

\frac{2 x ^{3} + ( - 5 - 2 i ) x ^{2} + ( 1 + i ) x + ( 2 + i )}{2 + i}

\frac{2 x ^{3} - 5 x ^{2} - 2 i x ^{2} + x + i x + 2 + i}{2 + i}

求解步骤

\frac{2 x ^{3} + ( - 5 - 2 i ) x ^{2} + ( 1 + i ) x + ( 2 + i )}{2 + i}

去除括号:

(a) = a

= \frac{2 x ^{3} + ( - 5 - 2 i ) x ^{2} + ( 1 + i ) x + 2 + i}{2 + i}

乘开

2 x^{3} + (- 5 - 2 i) x^{2} + (1 + i) x + 2 + i : 2 x^{3} - 5 x^{2} - 2 i x^{2} + x + i x + 2 + i

= \frac{2 x ^{3} - 5 x ^{2} - 2 i x ^{2} + x + i x + 2 + i}{2 + i}

e x p an d a + (b + c)

e x p an d \frac{- 3 a ^{2} x ( a - x ) ^{2} - 3 x z ^{2} ( a - x ) ^{2}}{2}

e x p an d π (- 128 ln (3) + \frac{808}{3})

e x p an d - \frac{2 x}{2 x + 3} + ln ∣ 2 x + 3 ∣ - \frac{3}{2 ( 2 x + 3 )}

e x p an d (\frac{x}{4} - \frac{2 x}{5} = \frac{x + 2}{20} - \frac{x + 1}{10}) \cdot 2