展开 (x/4-(2x)/5 =(x+2)/(20)-(x+1)/(10))*2

解答

展开

(\frac{x}{4} - \frac{2 x}{5} = \frac{x + 2}{20} - \frac{x + 1}{10}) \cdot 2

- \frac{3 x}{10} = - \frac{3 x}{20} - \frac{1}{10}

求解步骤

(\frac{x}{4} - \frac{2 x}{5} = \frac{x + 2}{20} - \frac{x + 1}{10}) \cdot 2

= 2 (\frac{x}{4} - = \frac{2 x}{5} \cdot \frac{x + 2}{20} - \frac{x + 1}{10})

打开括号

= 2 \cdot \frac{x}{4} + 2 (- \frac{2 x}{5} = \frac{x + 2}{20}) + 2 (- \frac{x + 1}{10})

使用加减运算法则

+ (- a) = - a

2 \cdot \frac{x}{4} - 2 \cdot \frac{2 x}{5} = \frac{x + 2}{20} - 2 \cdot \frac{x + 1}{10}

化简

2 \cdot \frac{x}{4} - 2 \cdot \frac{2 x}{5} = \frac{x + 2}{20} - 2 \cdot \frac{x + 1}{10} : - \frac{3 x}{10} = - \frac{3 x}{20} - \frac{1}{10}

- \frac{3 x}{10} = - \frac{3 x}{20} - \frac{1}{10}

e x p an d (a - 4 a x)^{2} + (b + 2 b x)^{2}

e x p an d \frac{z}{( z + 9 ) ^{2}}

e x p an d e^{3 x} (4 + e^{3 x})^{2}

\frac{d ^{2}}{d x ^{2}} ((y) e^{3 x} (1 + 3 x))

e x p an d 2 π (\frac{2}{9} - \frac{1}{18})