展开 ((b^4-6b^2a^2+8ba^3-3a^4))/((b-a)^2)

解答

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\frac{( b ^{4} - 6 b ^{2} a ^{2} + 8 b a ^{3} - 3 a ^{4} )}{( b - a ) ^{2}}

\frac{b ^{4} - 6 b ^{2} a ^{2} + 8 b a ^{3} - 3 a ^{4}}{b ^{2} - 2 ba + a ^{2}}

求解步骤

\frac{b ^{4} - 6 b ^{2} a ^{2} + 8 b a ^{3} - 3 a ^{4}}{( b - a ) ^{2}}

(b - a)^{2} = b^{2} - 2 ba + a^{2}

= \frac{b ^{4} - 6 b ^{2} a ^{2} + 8 b a ^{3} - 3 a ^{4}}{b ^{2} - 2 ba + a ^{2}}

e x p an d \frac{1}{( v + c ) ( v - c )}

e x p an d \frac{( ( sin ( x ) ) ( sin ( x ) - 1 ) ^{2} )}{1 - sin ^{x} ( x )}

e x p an d \frac{( 1 - 3 x ^{2} ) ^{2} ( x ^{2} + 3 )}{( 2 x + 1 ) ^{2} ( x ^{3} - 1 )}

e x p an d \frac{( 8 - 3 x ) ^{\frac{1}{3}}}{( 1 + 2 x ) ^{2}}

e x p an d T (x + 8, y - 1)