展开 (x-3)e^{|x+1|}

解答

展开

(x - 3) e^{∣ x + 1 ∣}

e^{∣ x + 1 ∣} x - 3 e^{∣ x + 1 ∣}

求解步骤

(x - 3) e^{∣ x + 1 ∣}

= e^{∣ x + 1 ∣} (x - 3)

使用分配律:

a (b - c) = ab - a c

a = e^{∣ x + 1 ∣}, b = x, c = 3

= e^{∣ x + 1 ∣} x - e^{∣ x + 1 ∣} \cdot 3

= e^{∣ x + 1 ∣} x - 3 e^{∣ x + 1 ∣}

e x p an d (t - 2) cos (3 t) e^{2 t}

e x p an d (\frac{a + x}{1 - a x})^{2}

e x p an d \frac{z ( 1.1353 z + 0.5941 )}{( z - 1 ) ( z ^{2} + 0.7294 )}

e x p an d \frac{3}{( x ^{2} + 4 ) \cdot ( x ^{2} + 9 )}

e x p an d π (2 x + 1)^{2} (6 x)