展开 1/(2sin(1/2 (θ+pi/6))+1)

解答

展开

\frac{1}{2 sin ( \frac{1}{2} ( θ + \frac{π}{6} ) ) + 1}

\frac{1}{\frac{6 + 2}{2} sin ( \frac{θ}{2} ) + \frac{6 - 2}{2} cos ( \frac{θ}{2} ) + 1}

求解步骤

\frac{1}{2 sin ( \frac{1}{2} ( θ + \frac{π}{6} ) ) + 1}

2 sin (\frac{1}{2} (θ + \frac{π}{6})) = 2 (\frac{6 + 2}{4} sin (\frac{θ}{2}) + \frac{6 - 2}{4} cos (\frac{θ}{2}))

= \frac{1}{2 ( \frac{6 + 2}{4} sin ( \frac{θ}{2} ) + \frac{6 - 2}{4} cos ( \frac{θ}{2} ) ) + 1}

乘开

2 (\frac{6 + 2}{4} sin (\frac{θ}{2}) + \frac{6 - 2}{4} cos (\frac{θ}{2})) + 1 : \frac{6 + 2}{2} sin (\frac{θ}{2}) + \frac{6 - 2}{2} cos (\frac{θ}{2}) + 1

= \frac{1}{\frac{6 + 2}{2} sin ( \frac{θ}{2} ) + \frac{6 - 2}{2} cos ( \frac{θ}{2} ) + 1}

e x p an d P (3, - 5) Q (- 2, 0)

e x p an d (1 + e^{x})^{4}

e x p an d \frac{4 ( x + h ) - 5 - 4 x - 5}{h}

e x p an d (a + b + c) (d + e)

e x p an d 3.42 e^{-} \cdot 79.7 (1 \cdot sin (225 x) + cos (225 x) \cdot 225 x)