展开 ((t^3)/3+1/(4t^2))dt

解答

展开

(\frac{t ^{3}}{3} + \frac{1}{4 t ^{2}}) d t

\frac{t ^{3} d t}{3} + \frac{d t}{4 t ^{2}}

求解步骤

(\frac{t ^{3}}{3} + \frac{1}{4 t ^{2}}) d t

使用分配律:

a (b + c) = ab + a c

a = d t, b = \frac{t ^{3}}{3}, c = \frac{1}{4 t ^{2}}

= d t \frac{t ^{3}}{3} + d t \frac{1}{4 t ^{2}}

= \frac{t ^{3}}{3} d t + \frac{1}{4 t ^{2}} d t

化简

\frac{t ^{3}}{3} d t + \frac{1}{4 t ^{2}} d t : \frac{t ^{3} d t}{3} + \frac{d t}{4 t ^{2}}

= \frac{t ^{3} d t}{3} + \frac{d t}{4 t ^{2}}

e x p an d (1 + e^{\frac{1}{x}})^{2}

s im pl i f y 1 + \frac{k}{( s + 1 ) ( s ^{2} + s + 1.5 )}

e x p an d \frac{( ( x + 4 ) ( 6 a + x - 4 ) )}{6}

\frac{\partial}{\partial x} ((z) (z^{3} - 3 x yz))

e x p an d \frac{1}{( x + 2 ) ( x + 1 )}