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人気のある代数 >

solvefor c,mba=nkc^2sp+mca

解

解く

c, m \cdot b \cdot a = n \cdot k \cdot c^{2} \cdot s \cdot p + m \cdot c \cdot a

解

c = \frac{- ma + m ^{2} a ^{2} + 4 mnkba s p}{2 nk s p}, c = \frac{- ma - m ^{2} a ^{2} + 4 mnkba s p}{2 nk s p}; nk s p \neq = 0

解答ステップ

mba = nk c^{2} s p + m c a

辺を交換する

nk c^{2} s p + m c a = mba

m \cdot b \cdot a

を左側に移動します

nk c^{2} s p + m c a - mba = 0

標準的な形式で書く

a x^{2} + b x + c = 0

nk s p c^{2} + ma c - mba = 0

解くとthe二次式

c_{1, 2} = \frac{- ma \pm ( ma ) ^{2} - 4 nk s p ( - mba )}{2 nk s p}

簡素化

(ma)^{2} - 4 nk s p (- mba) : m^{2} a^{2} + 4 mnkba s p

c_{1, 2} = \frac{- ma \pm m ^{2} a ^{2} + 4 mnkba s p}{2 nk s p}; nk s p \neq = 0

解を分離する

c_{1} = \frac{- ma + m ^{2} a ^{2} + 4 mnkba s p}{2 nk s p}, c_{2} = \frac{- ma - m ^{2} a ^{2} + 4 mnkba s p}{2 nk s p}

c = \frac{- ma + m ^{2} a ^{2} + 4 mnkba s p}{2 nk s p}; nk s p \neq = 0

c = \frac{- ma - m ^{2} a ^{2} + 4 mnkba s p}{2 nk s p}; nk s p \neq = 0

二次equationの解:

c = \frac{- ma + m ^{2} a ^{2} + 4 mnkba s p}{2 nk s p}, c = \frac{- ma - m ^{2} a ^{2} + 4 mnkba s p}{2 nk s p}; nk s p \neq = 0

グラフ

人気の例

x + 2 = - 3 x^{2}

x^{2} + 14 x + 65 = - 2

solvefor x,x^2+y^2+4x-2sqrt(3y)+3=0

so l v e f or x, x^{2} + y^{2} + 4 x - 2 3 y + 3 = 0

2 x^{2} + x + 15 = 0

((sqrt(5))/4)^2+y^2=1

(\frac{5}{4})^{2} + y^{2} = 1