2x^2-4x+4=2

解

2 x^{2} - 4 x + 4 = 2

x = 1

解答ステップ

2 x^{2} - 4 x + 4 = 2

2

を左側に移動します

2 x^{2} - 4 x + 2 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 \cdot 2 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 2}

x = \frac{- ( - 4 )}{2 \cdot 2}

\frac{- ( - 4 )}{2 \cdot 2} = 1

x = 1

二次equationの解:

x = 1