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受欢迎的代数 >

2k^2+9k+1=0

解答

2 k^{2} + 9 k + 1 = 0

解答

k = \frac{- 9 + 73}{4}, k = \frac{- 9 - 73}{4}

+1

十进制

k = - 0.11399 \dots, k = - 4.38600 \dots

求解步骤

2 k^{2} + 9 k + 1 = 0

使用求根公式求解

k_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

9^{2} - 4 \cdot 2 \cdot 1 = 73

k_{1, 2} = \frac{- 9 \pm 73}{2 \cdot 2}

将解分隔开

k_{1} = \frac{- 9 + 73}{2 \cdot 2}, k_{2} = \frac{- 9 - 73}{2 \cdot 2}

k = \frac{- 9 + 73}{2 \cdot 2} : \frac{- 9 + 73}{4}

k = \frac{- 9 - 73}{2 \cdot 2} : \frac{- 9 - 73}{4}

二次方程组的解是:

k = \frac{- 9 + 73}{4}, k = \frac{- 9 - 73}{4}

作图

流行的例子

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