p^2-p-12=0

解

p^{2} - p - 12 = 0

p = 4, p = - 3

解答ステップ

p^{2} - p - 12 = 0

解くとthe二次式

p_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 12) = 7

p_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 1}

解を分離する

p_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 1}, p_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 1}

p = \frac{- ( - 1 ) + 7}{2 \cdot 1} : 4

p = \frac{- ( - 1 ) - 7}{2 \cdot 1} : - 3

二次equationの解:

p = 4, p = - 3