x^2+x-182=0

解

x^{2} + x - 182 = 0

x = 13, x = - 14

解答ステップ

x^{2} + x - 182 = 0

解くとthe二次式

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 182 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 182) = 27

x_{1, 2} = \frac{- 1 \pm 27}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 1 + 27}{2 \cdot 1}, x_{2} = \frac{- 1 - 27}{2 \cdot 1}

x = \frac{- 1 + 27}{2 \cdot 1} : 13

x = \frac{- 1 - 27}{2 \cdot 1} : - 14

二次equationの解:

x = 13, x = - 14