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受欢迎的代数 >

a^2x^2+abx-2b^2=0

解答

a^{2} x^{2} + ab x - 2 b^{2} = 0

解答

x = \frac{b}{a}, x = - \frac{2 b}{a}; a \neq = 0

求解步骤

a^{2} x^{2} + ab x - 2 b^{2} = 0

使用求根公式求解

x_{1, 2} = \frac{- ab \pm ( ab ) ^{2} - 4 a ^{2} ( - 2 b ^{2} )}{2 a ^{2}}

化简

(ab)^{2} - 4 a^{2} (- 2 b^{2}) : 3 ab

x_{1, 2} = \frac{- ab \pm 3 ab}{2 a ^{2}}; a \neq = 0

将解分隔开

x_{1} = \frac{- ab + 3 ab}{2 a ^{2}}, x_{2} = \frac{- ab - 3 ab}{2 a ^{2}}

x = \frac{- ab + 3 ab}{2 a ^{2}} : \frac{b}{a}

x = \frac{- ab - 3 ab}{2 a ^{2}} : - \frac{2 b}{a}

二次方程组的解是:

x = \frac{b}{a}, x = - \frac{2 b}{a}; a \neq = 0

作图

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