What is (e^x+e^{-x})^2(e^x-e^{-x})^2 ?

The solution to (e^x+e^{-x})^2(e^x-e^{-x})^2 is (e^x+e^{-x})^2(e^x-e^{-x})^2

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simplify (e^x+e^{-x})^2(e^x-e^{-x})^2

simplify

(e^{x} + e^{- x})^{2} (e^{x} - e^{- x})^{2}

(e^{x} + e^{- x})^{2} (e^{x} - e^{- x})^{2}

Solution steps

(e^{x} + e^{- x})^{2} (e^{x} - e^{- x})^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(e^{x} + e^{- x})^{2} (e^{x} - e^{- x})^{2} = ((e^{x} + e^{- x}) (e^{x} - e^{- x}))^{2}

= ((e^{x} + e^{- x}) (e^{x} - e^{- x}))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (e^{x} + e^{- x})^{2} (e^{x} - e^{- x})^{2}

(ab c) (a^{2} b^{3})

- lo g_{10} (4.1) \times 1 0^{- 3}

12 3 a^{2} b

x^{2} e^{2}

(8 e)^{- 6}

What is (e^x+e^{-x})^2(e^x-e^{-x})^2 ?
The solution to (e^x+e^{-x})^2(e^x-e^{-x})^2 is (e^x+e^{-x})^2(e^x-e^{-x})^2