簡約-log_{10}(4.1)× 10^{-3}

解

簡約

- lo g_{10} (4.1) \cdot 1 0^{- 3}

- \frac{1}{1000} lo g_{10} (41) + \frac{1}{1000}

十進法表記

- 0.00061 \dots

解答ステップ

- lo g_{10} (4.1) \cdot 1 0^{- 3}

lo g_{10} (4.1) = lo g_{10} (41) - 1

= - (lo g_{10} (41) - 1) \cdot 1 0^{- 3}

- (lo g_{10} (41) - 1) \cdot 1 0^{- 3} = - \frac{1}{1000} lo g_{10} (41) + \frac{1}{1000}

= - \frac{1}{1000} lo g_{10} (41) + \frac{1}{1000}