What is (x^2+y)^2(x^2-y)^2(x^4+y^2)^2 ?

The solution to (x^2+y)^2(x^2-y)^2(x^4+y^2)^2 is (x^2+y)^2(x^2-y)^2(x^4+y^2)^2

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simplify (x^2+y)^2(x^2-y)^2(x^4+y^2)^2

simplify

(x^{2} + y)^{2} (x^{2} - y)^{2} (x^{4} + y^{2})^{2}

(x^{2} + y)^{2} (x^{2} - y)^{2} (x^{4} + y^{2})^{2}

Solution steps

(x^{2} + y)^{2} (x^{2} - y)^{2} (x^{4} + y^{2})^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x^{2} + y)^{2} (x^{2} - y)^{2} (x^{4} + y^{2})^{2} = ((x^{2} + y) (x^{2} - y) (x^{4} + y^{2}))^{2}

= ((x^{2} + y) (x^{2} - y) (x^{4} + y^{2}))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (x^{2} + y)^{2} (x^{2} - y)^{2} (x^{4} + y^{2})^{2}

3.6 \cdot 1 0^{- 1}

1.4 \cdot 1 0^{- 3}

(1 - x)^{- 3}

y

What is (x^2+y)^2(x^2-y)^2(x^4+y^2)^2 ?
The solution to (x^2+y)^2(x^2-y)^2(x^4+y^2)^2 is (x^2+y)^2(x^2-y)^2(x^4+y^2)^2