What is expand (2x^2+4x+2)/((x-3)(x+2)) ?

The solution to expand (2x^2+4x+2)/((x-3)(x+2)) is (2x^2+4x+2)/(x^2-x-6)

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expand (2x^2+4x+2)/((x-3)(x+2))

expand

\frac{2 x ^{2} + 4 x + 2}{( x - 3 ) ( x + 2 )}

\frac{2 x ^{2} + 4 x + 2}{x ^{2} - x - 6}

Solution steps

\frac{2 x ^{2} + 4 x + 2}{( x - 3 ) ( x + 2 )}

Expand

(x - 3) (x + 2) : x^{2} - x - 6

= \frac{2 x ^{2} + 4 x + 2}{x ^{2} - x - 6}

(1 + 2 sin (t)) (2 cos (t))

30.412 (x - 5) (\frac{x - 5}{2} + 5)

e^{x^{2} + 1} \cdot (1 + 2 \cdot x^{2})

\frac{n ^{2} ( n - 1 ) ^{2}}{2}

(5 x + 32 y) 2

What is expand (2x^2+4x+2)/((x-3)(x+2)) ?
The solution to expand (2x^2+4x+2)/((x-3)(x+2)) is (2x^2+4x+2)/(x^2-x-6)