What is expand-(2(t^2-1))/((t^2+1)^2) ?

The solution to expand-(2(t^2-1))/((t^2+1)^2) is -(2t^2-2)/(t^4+2t^2+1)

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expand-(2(t^2-1))/((t^2+1)^2)

expand

- \frac{2 ( t ^{2} - 1 )}{( t ^{2} + 1 ) ^{2}}

- \frac{2 t ^{2} - 2}{t ^{4} + 2 t ^{2} + 1}

Solution steps

- \frac{2 ( t ^{2} - 1 )}{( t ^{2} + 1 ) ^{2}}

(t^{2} + 1)^{2} = t^{4} + 2 t^{2} + 1

= - \frac{2 ( t ^{2} - 1 )}{t ^{4} + 2 t ^{2} + 1}

Expand

2 (t^{2} - 1) : 2 t^{2} - 2

= - \frac{2 t ^{2} - 2}{t ^{4} + 2 t ^{2} + 1}

\frac{sin ( x )}{( x - 1 ) ( x + 1 ) ^{2}}

- 1.8

lo g_{10} (x) (3 x - 4)

v (0, 0) f (0, - 3)

\frac{- 6 x ^{4} + 2}{( x ^{4} + 1 ) ^{2}}

What is expand-(2(t^2-1))/((t^2+1)^2) ?
The solution to expand-(2(t^2-1))/((t^2+1)^2) is -(2t^2-2)/(t^4+2t^2+1)