What is expand (2(x+Δx))/((x+Δx)-1) ?

The solution to expand (2(x+Δx))/((x+Δx)-1) is (2x+2Δx)/(x+Δx-1)

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expand (2(x+Δx))/((x+Δx)-1)

expand

\frac{2 ( x + Δ x )}{( x + Δ x ) - 1}

\frac{2 x + 2Δ x}{x + Δ x - 1}

Solution steps

\frac{2 ( x + Δ x )}{( x + Δ x ) - 1}

Remove parentheses:

(a) = a

= \frac{2 ( x + Δ x )}{x + Δ x - 1}

Expand

2 (x + Δ x) : 2 x + 2Δ x

= \frac{2 x + 2Δ x}{x + Δ x - 1}

\frac{5 ( x - 1 )}{2}

(- 3 + 1) (x + 3)^{2^{^{'}}} (- 3 - 1)^{'}

\frac{1}{( 3 e ^{- x} cos ( x ) - 2 e ^{- x} sin ( x ) ) ^{2}}

\frac{1}{s ( s + 3 ) ( s + 1 )}

What is expand (2(x+Δx))/((x+Δx)-1) ?
The solution to expand (2(x+Δx))/((x+Δx)-1) is (2x+2Δx)/(x+Δx-1)