What is expand (3-3sin(θ))^2 ?

The solution to expand (3-3sin(θ))^2 is 9-18sin(θ)+9sin^2(θ)

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expand (3-3sin(θ))^2

expand

(3 - 3 sin (θ))^{2}

9 - 18 sin (θ) + 9 sin^{2} (θ)

Solution steps

(3 - 3 sin (θ))^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(3 - 3 sin (θ))^{2} = 3^{2} - 2 \cdot 3 \cdot 3 sin (θ) + (3 sin (θ))^{2}

= 3^{2} - 2 \cdot 3 \cdot 3 sin (θ) + (3 sin (θ))^{2}

Simplify

3^{2} - 2 \cdot 3 \cdot 3 sin (θ) + (3 sin (θ))^{2} : 9 - 18 sin (θ) + 9 sin^{2} (θ)

= 9 - 18 sin (θ) + 9 sin^{2} (θ)

\frac{6}{( e ^{- j w} - 3 ) ( e ^{- j w} - 2 )}

(\frac{1}{3} - x) (\frac{1}{2} - x)

- x^{2} - 1

\frac{d y}{d x} + y (x e^{x^{2}} + 1)

49 (2 + \frac{π}{4})

What is expand (3-3sin(θ))^2 ?
The solution to expand (3-3sin(θ))^2 is 9-18sin(θ)+9sin^2(θ)