展开 e^{t-2}u(t-2)

解答

展开

e^{t - 2} u (t - 2)

e^{t - 2} t u - 2 e^{t - 2} u

求解步骤

e^{t - 2} u (t - 2)

使用分配律:

a (b - c) = ab - a c

a = e^{t - 2} u, b = t, c = 2

= e^{t - 2} u t - e^{t - 2} u \cdot 2

= e^{t - 2} t u - 2 e^{t - 2} u

e x p an d (x^{2} + y^{2}) d x + 4 x y d y

e x p an d lo g_{10} (4 \frac{a}{b})

e x p an d D x (2 x^{2} - 5 ln (x) - csc (x) - 1)

e x p an d \frac{1 - e ^{- x}}{x ( x ^{2} + 2 x + 26 )}

e x p an d 4 (3 e^{3 x} + 2 cos (2 x))^{3}