erweitern (x-1)/y (x-1)/y-1+1

Lösung

erweitern

\frac{x - 1}{y} \frac{x - 1}{y} - 1 + 1

\frac{x ^{2}}{y ^{2}} - \frac{2 x}{y ^{2}} + \frac{1}{y ^{2}}

Schritte zur Lösung

\frac{x - 1}{y} \cdot \frac{x - 1}{y} - 1 + 1

\frac{x - 1}{y} \cdot \frac{x - 1}{y} = \frac{x ^{2} - 2 x + 1}{y ^{2}}

= \frac{x ^{2} - 2 x + 1}{y ^{2}} - 1 + 1

- 1 + 1 = 0

= \frac{x ^{2} - 2 x + 1}{y ^{2}}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 2 x + 1}{y ^{2}} = \frac{x ^{2}}{y ^{2}} - \frac{2 x}{y ^{2}} + \frac{1}{y ^{2}}

= \frac{x ^{2}}{y ^{2}} - \frac{2 x}{y ^{2}} + \frac{1}{y ^{2}}

e x p an d lo g_{10} (a)

e x p an d (b - v f - d v)^{2}

e x p an d \frac{2 ^{r} ( r ^{2} - 2 )}{( r + 1 ) ^{2} ( r + 2 ) ^{2}}

e x p an d \frac{( 4 x - 1 ) ^{2}}{4}

e x p an d y \cdot (b^{2} - y^{2})