What is expand 1/((x-4)(x^2+1)) ?

The solution to expand 1/((x-4)(x^2+1)) is 1/(x^3+x-4x^2-4)

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expand 1/((x-4)(x^2+1))

expand

\frac{1}{( x - 4 ) ( x ^{2} + 1 )}

\frac{1}{x ^{3} + x - 4 x ^{2} - 4}

Solution steps

\frac{1}{( x - 4 ) ( x ^{2} + 1 )}

Expand

(x - 4) (x^{2} + 1) : x^{3} + x - 4 x^{2} - 4

= \frac{1}{x ^{3} + x - 4 x ^{2} - 4}

(z^{2} + cos (z)) (2 z - sin (z))

\frac{7 x}{( x + 6 ) ^{2}}

2 (1 + \frac{2 k}{n})

(2 y - 3) d y

(a c + \frac{3}{5}) (a c - \frac{3}{5})

What is expand 1/((x-4)(x^2+1)) ?
The solution to expand 1/((x-4)(x^2+1)) is 1/(x^3+x-4x^2-4)