展开 (0,-3,3)x(4,-2,0)

解答

展开

(0, - 3, 3) x (4, - 2, 0)

0 \cdot x, 4, - 0 \cdot x, 2, 0 - 3 x, 3 \cdot 4, 3, 3 \cdot 2, 0

求解步骤

(0, - 3, 3) x (4, - 2, 0)

= (0, - 3 \cdot 3,) (4, - 2 \cdot 0,) x

乘开

(0, - 3, 3) (4, - 2, 0) : 0, 4, - 0, 2, 0 - 3, 3 \cdot 4, 3, 3 \cdot 2, 0

= x (0, 4, - 0, 2, 0 - 3, 3 \cdot 4, 3, 3 \cdot 2, 0)

乘开

x (0, 4, - 0, 2, 0 - 3, 3 \cdot 4, 3, 3 \cdot 2, 0) : 0 \cdot x, 4, - 0 \cdot x, 2, 0 - 3 x, 3 \cdot 4, 3, 3 \cdot 2, 0

= 0 \cdot x, 4, - 0 \cdot x, 2, 0 - 3 x, 3 \cdot 4, 3, 3 \cdot 2, 0

\frac{d}{d t} ((x) (3 t^{2} - 8))

e x p an d \frac{( x - 4 ) ^{3}}{3}

e x p an d 3 + (- 2) i

e x p an d - e^{t} (cos (t) - sin (t))

e x p an d x^{\frac{4}{5}} (5 x - 20)^{2}