展開する c^{1/3}(c^{1/3}+c^{2/3})-1

解

展開する

c^{\frac{1}{3}} (c^{\frac{1}{3}} + c^{\frac{2}{3}}) - 1

c^{\frac{2}{3}} + c - 1

解答ステップ

c^{\frac{1}{3}} (c^{\frac{1}{3}} + c^{\frac{2}{3}}) - 1

分配法則を適用する:

a (b + c) = ab + a c

c^{\frac{1}{3}} (c^{\frac{1}{3}} + c^{\frac{2}{3}}) = c^{\frac{1}{3}} c^{\frac{1}{3}} + c^{\frac{1}{3}} c^{\frac{2}{3}}

= c^{\frac{1}{3}} c^{\frac{1}{3}} + c^{\frac{1}{3}} c^{\frac{2}{3}} - 1

c^{\frac{1}{3}} c^{\frac{1}{3}} = c^{\frac{2}{3}}

c^{\frac{1}{3}} c^{\frac{2}{3}} = c

= c^{\frac{2}{3}} + c - 1