展开 gen(1,-2,3)

解答

展开

g e n (1, - 2, 3)

1 e g n, - 2 e g n, 3

求解步骤

g e n (1, - 2, 3)

= e (1, - 2 \cdot 3,) g n

使用分配律:

a (b - c) = ab - a c

a = g e n, b = 1,, c = 2, 3

= g e n \cdot 1, - g e n \cdot 2, 3

= 1 e g n, - 2 e g n, 3

\frac{d}{d y} ((x) (e^{- 3 x} - (3 y + 1) x))

e x p an d (x - \frac{3}{2}) (x - \frac{3}{2})

e x p an d 3 (7 + 6)

s im pl i f y 3 (3 + 2)

e x p an d \frac{2 ( X + 1 )}{3}