展开 ((2+y)^2)/4

解答

展开

\frac{( 2 + y ) ^{2}}{4}

\frac{y ^{2}}{4} + y + 1

求解步骤

\frac{( 2 + y ) ^{2}}{4}

(2 + y)^{2} = 4 + 4 y + y^{2}

= \frac{4 + 4 y + y ^{2}}{4}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 + 4 y + y ^{2}}{4} = \frac{4}{4} + \frac{4 y}{4} + \frac{y ^{2}}{4}

= \frac{4}{4} + \frac{4 y}{4} + \frac{y ^{2}}{4}

使用法则

\frac{a}{a} = 1

\frac{4}{4} = 1

= 1 + \frac{4 y}{4} + \frac{y ^{2}}{4}

数字相除:

\frac{4}{4} = 1

= 1 + y + \frac{y ^{2}}{4}

改写为标准形式

= \frac{y ^{2}}{4} + y + 1

s im pl i f y (3 - 3 i)^{7}

e x p an d \frac{1}{( x ^{2} + 4 ) ( x + 2 )}

e x p an d 3 (\frac{3 π}{2} - \frac{9 3}{4})

e x p an d (7 - \frac{x ^{2}}{2})^{2}

e x p an d \frac{6}{( s ^{2} + 9 ) ^{2}}