展开 (e^{2t}-e^t)(e^{2t}+e^t)

解答

展开

(e^{2 t} - e^{t}) (e^{2 t} + e^{t})

e^{4 t} - e^{2 t}

求解步骤

(e^{2 t} - e^{t}) (e^{2 t} + e^{t})

使用平方差公式:

(a - b) (a + b) = a^{2} - b^{2}

a = e^{2 t}, b = e^{t}

= (e^{2 t})^{2} - (e^{t})^{2}

化简

(e^{2 t})^{2} - (e^{t})^{2} : e^{4 t} - e^{2 t}

= e^{4 t} - e^{2 t}

e x p an d \frac{1}{s ( s ^{2} + a ^{2} )}

e x p an d (2 + 3)^{2}

e x p an d \frac{0.6664 + 95.5 p}{p ( p - k )}

e x p an d (2 x - 3) lo g_{10} (2)

e x p an d e^{2 x} \cdot (e^{- 2 x} \cdot x + \frac{1}{2} e^{- 2 x} + c)