展开 ((xy+(1-δ)n))/(n_{1)(1+n_{1})}

解答

展开

\frac{( x y + ( 1 - δ ) n )}{n _{1} ( 1 + n _{1} )}

\frac{x y + n - δ n}{n _{1} + n _{1}^{2}}

求解步骤

\frac{x y + ( 1 - δ ) n}{n _{1} ( 1 + n _{1} )}

乘开

n_{1} (1 + n_{1}) : n_{1} + n_{1}^{2}

= \frac{x y + ( - δ + 1 ) n}{n _{1} + n _{1}^{2}}

乘开

x y + (1 - δ) n : x y + n - δ n

= \frac{x y + n - δ n}{n _{1} + n _{1}^{2}}

e x p an d (x + x^{2}) (3 x - 1)

e x p an d 3 x - 3 (x^{3} - 8)

e x p an d x (x^{2} - \frac{1}{x})

s im pl i f y (x - \frac{11}{3}) (x + \frac{11}{3})

e x p an d \frac{1 - e ^{- 2 s}}{s ( s ^{2} + 2 s + 2 )}