展开 32(ln(6x)+1)

解答

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32 (ln (6 x) + 1)

32 ln (6 x) + 32

求解步骤

32 (ln (6 x) + 1)

使用分配律:

a (b + c) = ab + a c

a = 32, b = ln (6 x), c = 1

= 32 ln (6 x) + 32 \cdot 1

数字相乘:

32 \cdot 1 = 32

= 32 ln (6 x) + 32

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