展开 ((x-2)(x-4))/8

解答

展开

\frac{( x - 2 ) ( x - 4 )}{8}

\frac{x ^{2}}{8} - \frac{3 x}{4} + 1

求解步骤

\frac{( x - 2 ) ( x - 4 )}{8}

乘开

(x - 2) (x - 4) : x^{2} - 6 x + 8

= \frac{x ^{2} - 6 x + 8}{8}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 6 x + 8}{8} = \frac{x ^{2}}{8} - \frac{6 x}{8} + \frac{8}{8}

= \frac{x ^{2}}{8} - \frac{6 x}{8} + \frac{8}{8}

使用法则

\frac{a}{a} = 1

\frac{8}{8} = 1

= \frac{x ^{2}}{8} - \frac{6 x}{8} + 1

消掉

\frac{6 x}{8} : \frac{3 x}{4}

= \frac{x ^{2}}{8} - \frac{3 x}{4} + 1

e x p an d \frac{1}{( 1 - x ) ( a - 2 x )}

e x p an d lo g_{10} (\frac{9 x - 6}{x + 6})

e x p an d 3 (2 - 1)

e x p an d \frac{3}{s ^{2} ( s ^{2} - 9 )}

s im pl i f y (x - 1) (x - \frac{1}{2})