-2x^2+12x=0

解

- 2 x^{2} + 12 x = 0

x = 0, x = 6

解答ステップ

- 2 x^{2} + 12 x = 0

解くとthe二次式

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

1 2^{2} - 4 (- 2) \cdot 0 = 12

x_{1, 2} = \frac{- 12 \pm 12}{2 ( - 2 )}

解を分離する

x_{1} = \frac{- 12 + 12}{2 ( - 2 )}, x_{2} = \frac{- 12 - 12}{2 ( - 2 )}

x = \frac{- 12 + 12}{2 ( - 2 )} : 0

x = \frac{- 12 - 12}{2 ( - 2 )} : 6

二次equationの解:

x = 0, x = 6