(1/27)^{2d-2}<= 81^{d+4}

解

(\frac{1}{27})^{2 d - 2} \leq 8 1^{d + 4}

d \geq - 1

区間表記

[- 1, \infty)

解答ステップ

(\frac{1}{27})^{2 d - 2} \leq 8 1^{d + 4}

f (x) \leq g (x)

の場合は

ln (f (x)) \leq ln (g (x))

ln ((\frac{1}{27})^{2 d - 2}) \leq ln (8 1^{d + 4})

簡素化

ln ((\frac{1}{27})^{2 d - 2}) : - 3 ln (3) (2 d - 2)

簡素化

ln (8 1^{d + 4}) : 4 ln (3) (d + 4)

- 3 ln (3) (2 d - 2) \leq 4 ln (3) (d + 4)

- 3 ln (3) (2 d - 2) \leq 4 ln (3) (d + 4) : d \geq - 1

d \geq - 1