# Evaluating Square Roots

When the square root of a number is squared, the result is the original number. Since [latex]{4}^{2}=16[/latex], the square root of [latex]16[/latex] is [latex]4[/latex]. The square root function is the inverse of the squaring function just as subtraction is the inverse of addition. To undo squaring, we take the square root. In general terms, if [latex]a[/latex] is a positive real number, then the square root of [latex]a[/latex] is a number that, when multiplied by itself, gives [latex]a[/latex]. The square root could be positive or negative because multiplying two negative numbers gives a positive number. The**principal square root**is the nonnegative number that when multiplied by itself equals [latex]a[/latex]. The square root obtained using a calculator is the principal square root. The principal square root of [latex]a[/latex] is written as [latex]\sqrt{a}[/latex]. The symbol is called a

**radical**, the term under the symbol is called the

**radicand**, and the entire expression is called a

**radical expression**.

### A General Note: Principal Square Root

The**principal square root**of [latex]a[/latex] is the nonnegative number that, when multiplied by itself, equals [latex]a[/latex]. It is written as a

**radical expression**, with a symbol called a

**radical**over the term called the

**radicand**: [latex]\sqrt{a}[/latex].

### Q & A

**Does** [latex]\sqrt{25}=\pm 5[/latex]?

*No. Although both*[latex]{5}^{2}[/latex]

*and*[latex]{\left(-5\right)}^{2}[/latex]

*are*[latex]25[/latex],

*the radical symbol implies only a nonnegative root, the principal square root. The principal square root of 25 is*[latex]\sqrt{25}=5[/latex].

### Example 1: Evaluating Square Roots

Evaluate each expression.- [latex]\sqrt{100}[/latex]
- [latex]\sqrt{\sqrt{16}}[/latex]
- [latex]\sqrt{25+144}[/latex]
- [latex]\sqrt{49}-\sqrt{81}\\[/latex]

### Solution

- [latex]\sqrt{100}=10[/latex] because [latex]{10}^{2}=100[/latex]
- [latex]\sqrt{\sqrt{16}}=\sqrt{4}=2[/latex] because [latex]{4}^{2}=16[/latex] and [latex]{2}^{2}=4[/latex]
- [latex]\sqrt{25+144}=\sqrt{169}=13[/latex] because [latex]{13}^{2}=169[/latex]
- [latex]\sqrt{49}-\sqrt{81}=7 - 9=-2[/latex] because [latex]{7}^{2}=49[/latex] and [latex]{9}^{2}=81[/latex]

### Q & A

### For [latex]\sqrt{25+144}[/latex], can we find the square roots before adding?

*No.*[latex]\sqrt{25}+\sqrt{144}=5+12=17[/latex].

*This is not equivalent to*[latex]\sqrt{25+144}=13[/latex].

*The order of operations requires us to add the terms in the radicand before finding the square root.*

### Try It 1

Evaluate each expression.a. [latex]\sqrt{225}[/latex] b. [latex]\sqrt{\sqrt{81}}[/latex] c. [latex]\sqrt{25 - 9}[/latex] d. [latex]\sqrt{36}+\sqrt{121}[/latex]

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