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Popolare Trigonometria >

solvefor t,v=311cos(30t+30)v

Soluzione

risolvere per

t, v = 311 cos (30 t + 3 0^{\circ}) v

Soluzione

t = \frac{18 0 ^{\circ} n}{15} - 1^{\circ} + \frac{1.56758 \dots}{30}, t = 1 2^{\circ} - 1^{\circ} + \frac{18 0 ^{\circ} n}{15} - \frac{1.56758 \dots}{30}

Radianti

t = - \frac{π}{180} + \frac{1.56758 \dots}{30} + \frac{π}{15} n, t = \frac{π}{15} - \frac{π}{180} - \frac{1.56758 \dots}{30} + \frac{π}{15} n

Fasi della soluzione

v = 311 cos (30 t + 3 0^{\circ}) v

Scambia i lati

311 cos (30 t + \frac{π}{6}) v = v

Dividere entrambi i lati per

311 v; v \neq = 0

311 cos (30 t + \frac{π}{6}) v = v

Dividere entrambi i lati per

311 v; v \neq = 0

\frac{311 cos ( 30 t + \frac{π}{6} ) v}{311 v} = \frac{v}{311 v}; v \neq = 0

Semplificare

cos (30 t + \frac{π}{6}) = \frac{1}{311}; v \neq = 0

cos (30 t + \frac{π}{6}) = \frac{1}{311}; v \neq = 0

Applica le proprietà inverse delle funzioni trigonometriche

cos (30 t + 3 0^{\circ}) = \frac{1}{311}

Soluzioni generali per

cos (30 t + 3 0^{\circ}) = \frac{1}{311}

cos (x) = a \Rightarrow x = arccos (a) + 36 0^{\circ} n, x = 36 0^{\circ} - arccos (a) + 36 0^{\circ} n

30 t + 3 0^{\circ} = arccos (\frac{1}{311}) + 36 0^{\circ} n, 30 t + 3 0^{\circ} = 36 0^{\circ} - arccos (\frac{1}{311}) + 36 0^{\circ} n

30 t + 3 0^{\circ} = arccos (\frac{1}{311}) + 36 0^{\circ} n, 30 t + 3 0^{\circ} = 36 0^{\circ} - arccos (\frac{1}{311}) + 36 0^{\circ} n

Risolvi

30 t + 3 0^{\circ} = arccos (\frac{1}{311}) + 36 0^{\circ} n : t = \frac{18 0 ^{\circ} n}{15} - 1^{\circ} + \frac{arccos ( \frac{1}{311} )}{30}

30 t + 3 0^{\circ} = arccos (\frac{1}{311}) + 36 0^{\circ} n

Spostare

3 0^{\circ}

a destra dell'equazione

30 t + 3 0^{\circ} = arccos (\frac{1}{311}) + 36 0^{\circ} n

Sottrarre

3 0^{\circ}

da entrambi i lati

30 t + 3 0^{\circ} - 3 0^{\circ} = arccos (\frac{1}{311}) + 36 0^{\circ} n - 3 0^{\circ}

Semplificare

30 t = arccos (\frac{1}{311}) + 36 0^{\circ} n - 3 0^{\circ}

30 t = arccos (\frac{1}{311}) + 36 0^{\circ} n - 3 0^{\circ}

Dividere entrambi i lati per

30

30 t = arccos (\frac{1}{311}) + 36 0^{\circ} n - 3 0^{\circ}

Dividere entrambi i lati per

30

\frac{30 t}{30} = \frac{arccos ( \frac{1}{311} )}{30} + \frac{36 0 ^{\circ} n}{30} - \frac{3 0 ^{\circ}}{30}

Semplificare

\frac{30 t}{30} = \frac{arccos ( \frac{1}{311} )}{30} + \frac{36 0 ^{\circ} n}{30} - \frac{3 0 ^{\circ}}{30}

Semplificare

\frac{30 t}{30} : t

\frac{30 t}{30}

Dividi i numeri:

\frac{30}{30} = 1

= t

Semplificare

\frac{arccos ( \frac{1}{311} )}{30} + \frac{36 0 ^{\circ} n}{30} - \frac{3 0 ^{\circ}}{30} : \frac{18 0 ^{\circ} n}{15} - 1^{\circ} + \frac{arccos ( \frac{1}{311} )}{30}

\frac{arccos ( \frac{1}{311} )}{30} + \frac{36 0 ^{\circ} n}{30} - \frac{3 0 ^{\circ}}{30}

Raggruppa termini simili

= \frac{36 0 ^{\circ} n}{30} - \frac{3 0 ^{\circ}}{30} + \frac{arccos ( \frac{1}{311} )}{30}

\frac{36 0 ^{\circ} n}{30} = \frac{18 0 ^{\circ} n}{15}

\frac{36 0 ^{\circ} n}{30}

Cancella il fattore comune:

2

= \frac{18 0 ^{\circ} n}{15}

\frac{3 0 ^{\circ}}{30} = 1^{\circ}

\frac{3 0 ^{\circ}}{30}

Applica la regola delle frazioni:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{18 0 ^{\circ}}{6 \cdot 30}

Moltiplica i numeri:

6 \cdot 30 = 180

= 1^{\circ}

= \frac{18 0 ^{\circ} n}{15} - 1^{\circ} + \frac{arccos ( \frac{1}{311} )}{30}

t = \frac{18 0 ^{\circ} n}{15} - 1^{\circ} + \frac{arccos ( \frac{1}{311} )}{30}

t = \frac{18 0 ^{\circ} n}{15} - 1^{\circ} + \frac{arccos ( \frac{1}{311} )}{30}

t = \frac{18 0 ^{\circ} n}{15} - 1^{\circ} + \frac{arccos ( \frac{1}{311} )}{30}

Risolvi

30 t + 3 0^{\circ} = 36 0^{\circ} - arccos (\frac{1}{311}) + 36 0^{\circ} n : t = 1 2^{\circ} - 1^{\circ} + \frac{18 0 ^{\circ} n}{15} - \frac{arccos ( \frac{1}{311} )}{30}

30 t + 3 0^{\circ} = 36 0^{\circ} - arccos (\frac{1}{311}) + 36 0^{\circ} n

Spostare

3 0^{\circ}

a destra dell'equazione

30 t + 3 0^{\circ} = 36 0^{\circ} - arccos (\frac{1}{311}) + 36 0^{\circ} n

Sottrarre

3 0^{\circ}

da entrambi i lati

30 t + 3 0^{\circ} - 3 0^{\circ} = 36 0^{\circ} - arccos (\frac{1}{311}) + 36 0^{\circ} n - 3 0^{\circ}

Semplificare

30 t = 36 0^{\circ} - arccos (\frac{1}{311}) + 36 0^{\circ} n - 3 0^{\circ}

30 t = 36 0^{\circ} - arccos (\frac{1}{311}) + 36 0^{\circ} n - 3 0^{\circ}

Dividere entrambi i lati per

30

30 t = 36 0^{\circ} - arccos (\frac{1}{311}) + 36 0^{\circ} n - 3 0^{\circ}

Dividere entrambi i lati per

30

\frac{30 t}{30} = 1 2^{\circ} - \frac{arccos ( \frac{1}{311} )}{30} + \frac{36 0 ^{\circ} n}{30} - \frac{3 0 ^{\circ}}{30}

Semplificare

\frac{30 t}{30} = 1 2^{\circ} - \frac{arccos ( \frac{1}{311} )}{30} + \frac{36 0 ^{\circ} n}{30} - \frac{3 0 ^{\circ}}{30}

Semplificare

\frac{30 t}{30} : t

\frac{30 t}{30}

Dividi i numeri:

\frac{30}{30} = 1

= t

Semplificare

1 2^{\circ} - \frac{arccos ( \frac{1}{311} )}{30} + \frac{36 0 ^{\circ} n}{30} - \frac{3 0 ^{\circ}}{30} : 1 2^{\circ} - 1^{\circ} + \frac{18 0 ^{\circ} n}{15} - \frac{arccos ( \frac{1}{311} )}{30}

1 2^{\circ} - \frac{arccos ( \frac{1}{311} )}{30} + \frac{36 0 ^{\circ} n}{30} - \frac{3 0 ^{\circ}}{30}

Raggruppa termini simili

= 1 2^{\circ} + \frac{36 0 ^{\circ} n}{30} - \frac{3 0 ^{\circ}}{30} - \frac{arccos ( \frac{1}{311} )}{30}

1 2^{\circ} = 1 2^{\circ}

1 2^{\circ}

Cancella il fattore comune:

2

= 1 2^{\circ}

\frac{36 0 ^{\circ} n}{30} = \frac{18 0 ^{\circ} n}{15}

\frac{36 0 ^{\circ} n}{30}

Cancella il fattore comune:

2

= \frac{18 0 ^{\circ} n}{15}

\frac{3 0 ^{\circ}}{30} = 1^{\circ}

\frac{3 0 ^{\circ}}{30}

Applica la regola delle frazioni:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{18 0 ^{\circ}}{6 \cdot 30}

Moltiplica i numeri:

6 \cdot 30 = 180

= 1^{\circ}

= 1 2^{\circ} + \frac{18 0 ^{\circ} n}{15} - 1^{\circ} - \frac{arccos ( \frac{1}{311} )}{30}

Raggruppa termini simili

= 1 2^{\circ} - 1^{\circ} + \frac{18 0 ^{\circ} n}{15} - \frac{arccos ( \frac{1}{311} )}{30}

t = 1 2^{\circ} - 1^{\circ} + \frac{18 0 ^{\circ} n}{15} - \frac{arccos ( \frac{1}{311} )}{30}

t = 1 2^{\circ} - 1^{\circ} + \frac{18 0 ^{\circ} n}{15} - \frac{arccos ( \frac{1}{311} )}{30}

t = 1 2^{\circ} - 1^{\circ} + \frac{18 0 ^{\circ} n}{15} - \frac{arccos ( \frac{1}{311} )}{30}

t = \frac{18 0 ^{\circ} n}{15} - 1^{\circ} + \frac{arccos ( \frac{1}{311} )}{30}, t = 1 2^{\circ} - 1^{\circ} + \frac{18 0 ^{\circ} n}{15} - \frac{arccos ( \frac{1}{311} )}{30}

Mostra le soluzioni in forma decimale

t = \frac{18 0 ^{\circ} n}{15} - 1^{\circ} + \frac{1.56758 \dots}{30}, t = 1 2^{\circ} - 1^{\circ} + \frac{18 0 ^{\circ} n}{15} - \frac{1.56758 \dots}{30}

Grafico

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