sin(θ)=-2/3 ,180<θ<270

Lösung

sin (θ) = - \frac{2}{3}, 18 0^{\circ} < θ < 27 0^{\circ}

θ = 18 0^{\circ} + 0.72972 \dots

Radianten

θ = π + 0.72972 \dots

Schritte zur Lösung

sin (θ) = - \frac{2}{3}, 18 0^{\circ} < θ < 27 0^{\circ}

Wende die Eigenschaften der Trigonometrie an

sin (θ) = - \frac{2}{3}

Allgemeine Lösung für

sin (θ) = - \frac{2}{3}

sin (x) = - a \Rightarrow x = arcsin (- a) + 36 0^{\circ} n, x = 18 0^{\circ} + arcsin (a) + 36 0^{\circ} n

θ = arcsin (- \frac{2}{3}) + 36 0^{\circ} n, θ = 18 0^{\circ} + arcsin (\frac{2}{3}) + 36 0^{\circ} n

θ = arcsin (- \frac{2}{3}) + 36 0^{\circ} n, θ = 18 0^{\circ} + arcsin (\frac{2}{3}) + 36 0^{\circ} n

Lösungen für den Bereich

18 0^{\circ} < θ < 27 0^{\circ}

θ = 18 0^{\circ} + arcsin (\frac{2}{3})

Zeige Lösungen in Dezimalform

θ = 18 0^{\circ} + 0.72972 \dots

so l v e f or x, R f = e^{c o s (2 x)}

sin (2 θ) = \frac{12}{13}

sin^{2} (θ) + sin (θ) = 2

7 sin^{2} (θ) - 3 sin (θ) = 4

- 5 - 4 tan (θ) = - 1