解答
3sin(x)=2sec(x)tan(x)
解答
x=2πn,x=π+2πn,x=2.52611…+2πn,x=−2.52611…+2πn,x=0.61547…+2πn,x=2π−0.61547…+2πn
+1
度数
x=0∘+360∘n,x=180∘+360∘n,x=144.73561…∘+360∘n,x=−144.73561…∘+360∘n,x=35.26438…∘+360∘n,x=324.73561…∘+360∘n求解步骤
3sin(x)=2sec(x)tan(x)
两边减去 2sec(x)tan(x)3sin(x)−2sec(x)tan(x)=0
用 sin, cos 表示
3sin(x)−2sec(x)tan(x)
使用基本三角恒等式: sec(x)=cos(x)1=3sin(x)−2⋅cos(x)1tan(x)
使用基本三角恒等式: tan(x)=cos(x)sin(x)=3sin(x)−2⋅cos(x)1⋅cos(x)sin(x)
化简 3sin(x)−2⋅cos(x)1⋅cos(x)sin(x):cos2(x)3cos2(x)sin(x)−2sin(x)
3sin(x)−2⋅cos(x)1⋅cos(x)sin(x)
2⋅cos(x)1⋅cos(x)sin(x)=cos2(x)2sin(x)
2⋅cos(x)1⋅cos(x)sin(x)
分式相乘: a⋅cb⋅ed=c⋅ea⋅b⋅d=cos(x)cos(x)1⋅sin(x)⋅2
数字相乘:1⋅2=2=cos(x)cos(x)2sin(x)
cos(x)cos(x)=cos2(x)
cos(x)cos(x)
使用指数法则: ab⋅ac=ab+ccos(x)cos(x)=cos1+1(x)=cos1+1(x)
数字相加:1+1=2=cos2(x)
=cos2(x)2sin(x)
=3sin(x)−cos2(x)2sin(x)
将项转换为分式: 3sin(x)=cos2(x)3sin(x)cos2(x)=cos2(x)3sin(x)cos2(x)−cos2(x)2sin(x)
因为分母相等,所以合并分式: ca±cb=ca±b=cos2(x)3sin(x)cos2(x)−2sin(x)
=cos2(x)3cos2(x)sin(x)−2sin(x)
cos2(x)−2sin(x)+3cos2(x)sin(x)=0
g(x)f(x)=0⇒f(x)=0−2sin(x)+3cos2(x)sin(x)=0
分解 −2sin(x)+3cos2(x)sin(x):sin(x)(3cos(x)+2)(3cos(x)−2)
−2sin(x)+3cos2(x)sin(x)
因式分解出通项 sin(x)=sin(x)(−2+3cos2(x))
分解 3cos2(x)−2:(3cos(x)+2)(3cos(x)−2)
3cos2(x)−2
将 3cos2(x)−2 改写为 (3cos(x))2−(2)2
3cos2(x)−2
使用根式运算法则: a=(a)23=(3)2=(3)2cos2(x)−2
使用根式运算法则: a=(a)22=(2)2=(3)2cos2(x)−(2)2
使用指数法则: ambm=(ab)m(3)2cos2(x)=(3cos(x))2=(3cos(x))2−(2)2
=(3cos(x))2−(2)2
使用平方差公式: x2−y2=(x+y)(x−y)(3cos(x))2−(2)2=(3cos(x)+2)(3cos(x)−2)=(3cos(x)+2)(3cos(x)−2)
=sin(x)(3cos(x)+2)(3cos(x)−2)
sin(x)(3cos(x)+2)(3cos(x)−2)=0
分别求解每个部分sin(x)=0or3cos(x)+2=0or3cos(x)−2=0
sin(x)=0:x=2πn,x=π+2πn
sin(x)=0
sin(x)=0的通解
sin(x) 周期表(周期为 2πn"):
x06π4π3π2π32π43π65πsin(x)02122231232221xπ67π45π34π23π35π47π611πsin(x)0−21−22−23−1−23−22−21
x=0+2πn,x=π+2πn
x=0+2πn,x=π+2πn
解 x=0+2πn:x=2πn
x=0+2πn
0+2πn=2πnx=2πn
x=2πn,x=π+2πn
3cos(x)+2=0:x=arccos(−32)+2πn,x=−arccos(−32)+2πn
3cos(x)+2=0
将 2到右边
3cos(x)+2=0
两边减去 23cos(x)+2−2=0−2
化简3cos(x)=−2
3cos(x)=−2
两边除以 3
3cos(x)=−2
两边除以 333cos(x)=3−2
化简
33cos(x)=3−2
化简 33cos(x):cos(x)
33cos(x)
约分:3=cos(x)
化简 3−2:−32
3−2
使用分式法则: b−a=−ba=−32
合并相同指数项 : yx=yx=−32
cos(x)=−32
cos(x)=−32
cos(x)=−32
使用反三角函数性质
cos(x)=−32
cos(x)=−32的通解cos(x)=−a⇒x=arccos(−a)+2πn,x=−arccos(−a)+2πnx=arccos(−32)+2πn,x=−arccos(−32)+2πn
x=arccos(−32)+2πn,x=−arccos(−32)+2πn
3cos(x)−2=0:x=arccos(32)+2πn,x=2π−arccos(32)+2πn
3cos(x)−2=0
将 2到右边
3cos(x)−2=0
两边加上 23cos(x)−2+2=0+2
化简3cos(x)=2
3cos(x)=2
两边除以 3
3cos(x)=2
两边除以 333cos(x)=32
化简
33cos(x)=32
化简 33cos(x):cos(x)
33cos(x)
约分:3=cos(x)
化简 32:32
32
合并相同指数项 : yx=yx=32
cos(x)=32
cos(x)=32
cos(x)=32
使用反三角函数性质
cos(x)=32
cos(x)=32的通解cos(x)=a⇒x=arccos(a)+2πn,x=2π−arccos(a)+2πnx=arccos(32)+2πn,x=2π−arccos(32)+2πn
x=arccos(32)+2πn,x=2π−arccos(32)+2πn
合并所有解x=2πn,x=π+2πn,x=arccos(−32)+2πn,x=−arccos(−32)+2πn,x=arccos(32)+2πn,x=2π−arccos(32)+2πn
以小数形式表示解x=2πn,x=π+2πn,x=2.52611…+2πn,x=−2.52611…+2πn,x=0.61547…+2πn,x=2π−0.61547…+2πn