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인기 있는 삼각법 >

1/(6tan^6(x))= 1/(6sec^6(x))

해법

\frac{1}{6 tan ^{6} ( x )} = \frac{1}{6 sec ^{6} ( x )}

해법

솔루션 없음 x \in R

솔루션 단계

\frac{1}{6 tan ^{6} ( x )} = \frac{1}{6 sec ^{6} ( x )}

빼다

\frac{1}{6 sec ^{6} ( x )}

양쪽에서

\frac{1}{6 tan ^{6} ( x )} - \frac{1}{6 sec ^{6} ( x )} = 0

\frac{1}{6 tan ^{6} ( x )} - \frac{1}{6 sec ^{6} ( x )}

단순화하세요:

\frac{sec ^{6} ( x ) - tan ^{6} ( x )}{6 tan ^{6} ( x ) sec ^{6} ( x )}

\frac{1}{6 tan ^{6} ( x )} - \frac{1}{6 sec ^{6} ( x )}

6 tan^{6} (x), 6 sec^{6} (x)

의 최소 공배수:

6 tan^{6} (x) sec^{6} (x)

6 tan^{6} (x), 6 sec^{6} (x)

최저공통승수 (LCM)

6, 6

의 최소 공배수:

6

6, 6

최소공배수 (LCM)

의 주요 인수 분해

6 : 2 \cdot 3

6

6

로 나누다

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

모두 소수이므로 더 이상의 인수 분해는 불가능하다

= 2 \cdot 3

의 주요 인수 분해

6 : 2 \cdot 3

6

6

로 나누다

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

모두 소수이므로 더 이상의 인수 분해는 불가능하다

= 2 \cdot 3

다음 중 하나에서 발생하는 가장 큰 횟수를 각 인자에 곱합니다

6

혹은

6

= 2 \cdot 3

숫자를 곱하시오:

2 \cdot 3 = 6

= 6

다음 중 하나에 나타나는 요인으로 구성된 식을 계산합니다

6 tan^{6} (x)

혹은

6 sec^{6} (x)

= 6 tan^{6} (x) sec^{6} (x)

LCM을 기준으로 분수 조정

각 분자를 곱하는 데 필요한 동일한 양으로 곱하시오

해당 분모를 LCM으로 변환합니다

6 tan^{6} (x) sec^{6} (x)

위해서

\frac{1}{6 tan ^{6} ( x )} :

분모와 분자를 곱하다

sec^{6} (x)

\frac{1}{6 tan ^{6} ( x )} = \frac{1 \cdot sec ^{6} ( x )}{6 tan ^{6} ( x ) sec ^{6} ( x )} = \frac{sec ^{6} ( x )}{6 tan ^{6} ( x ) sec ^{6} ( x )}

위해서

\frac{1}{6 sec ^{6} ( x )} :

분모와 분자를 곱하다

tan^{6} (x)

\frac{1}{6 sec ^{6} ( x )} = \frac{1 \cdot tan ^{6} ( x )}{6 sec ^{6} ( x ) tan ^{6} ( x )} = \frac{tan ^{6} ( x )}{6 tan ^{6} ( x ) sec ^{6} ( x )}

= \frac{sec ^{6} ( x )}{6 tan ^{6} ( x ) sec ^{6} ( x )} - \frac{tan ^{6} ( x )}{6 tan ^{6} ( x ) sec ^{6} ( x )}

분모가 같기 때문에, 분수를 합친다:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{sec ^{6} ( x ) - tan ^{6} ( x )}{6 tan ^{6} ( x ) sec ^{6} ( x )}

\frac{sec ^{6} ( x ) - tan ^{6} ( x )}{6 tan ^{6} ( x ) sec ^{6} ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

sec^{6} (x) - tan^{6} (x) = 0

sec^{6} (x) - tan^{6} (x)

요인:

(sec (x) + tan (x)) (sec^{2} (x) - sec (x) tan (x) + tan^{2} (x)) (sec (x) - tan (x)) (sec^{2} (x) + sec (x) tan (x) + tan^{2} (x))

sec^{6} (x) - tan^{6} (x)

sec^{6} (x) - tan^{6} (x) (sec^{3} (x))^{2} - (tan^{3} (x))^{2}

로 다시 씁니다

sec^{6} (x) - tan^{6} (x)

지수 규칙 적용:

a^{b c} = (a^{b})^{c}

sec^{6} (x) = (sec^{3} (x))^{2}

= (sec^{3} (x))^{2} - tan^{6} (x)

지수 규칙 적용:

a^{b c} = (a^{b})^{c}

tan^{6} (x) = (tan^{3} (x))^{2}

= (sec^{3} (x))^{2} - (tan^{3} (x))^{2}

= (sec^{3} (x))^{2} - (tan^{3} (x))^{2}

두 제곱 공식의 차이 적용:

x^{2} - y^{2} = (x + y) (x - y)

(sec^{3} (x))^{2} - (tan^{3} (x))^{2} = (sec^{3} (x) + tan^{3} (x)) (sec^{3} (x) - tan^{3} (x))

= (sec^{3} (x) + tan^{3} (x)) (sec^{3} (x) - tan^{3} (x))

sec^{3} (x) + tan^{3} (x)

요인:

(sec (x) + tan (x)) (sec^{2} (x) - sec (x) tan (x) + tan^{2} (x))

sec^{3} (x) + tan^{3} (x)

입방체의 합 공식 적용:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

sec^{3} (x) + tan^{3} (x) = (sec (x) + tan (x)) (sec^{2} (x) - sec (x) tan (x) + tan^{2} (x))

= (sec (x) + tan (x)) (sec^{2} (x) - sec (x) tan (x) + tan^{2} (x))

= (sec (x) + tan (x)) (sec^{2} (x) - sec (x) tan (x) + tan^{2} (x)) (sec^{3} (x) - tan^{3} (x))

sec^{3} (x) - tan^{3} (x)

요인:

(sec (x) - tan (x)) (sec^{2} (x) + sec (x) tan (x) + tan^{2} (x))

sec^{3} (x) - tan^{3} (x)

입방체의 차이 공식 적용:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

sec^{3} (x) - tan^{3} (x) = (sec (x) - tan (x)) (sec^{2} (x) + sec (x) tan (x) + tan^{2} (x))

= (sec (x) - tan (x)) (sec^{2} (x) + sec (x) tan (x) + tan^{2} (x))

= (sec (x) + tan (x)) (sec^{2} (x) - sec (x) tan (x) + tan^{2} (x)) (sec (x) - tan (x)) (sec^{2} (x) + sec (x) tan (x) + tan^{2} (x))

(sec (x) + tan (x)) (sec^{2} (x) - sec (x) tan (x) + tan^{2} (x)) (sec (x) - tan (x)) (sec^{2} (x) + sec (x) tan (x) + tan^{2} (x)) = 0

삼각성을 사용하여 다시 쓰기

(sec (x) + tan (x)) (sec^{2} (x) - sec (x) tan (x) + tan^{2} (x)) (sec (x) - tan (x)) (sec^{2} (x) + sec (x) tan (x) + tan^{2} (x))

(sec (x) + tan (x)) (sec (x) - tan (x)) = 1

(sec (x) + tan (x)) (sec (x) - tan (x))

(sec (x) + tan (x)) (sec (x) - tan (x))

확대한다:

sec^{2} (x) - tan^{2} (x)

(sec (x) + tan (x)) (sec (x) - tan (x))

두 제곱 공식의 차이 적용:

(a + b) (a - b) = a^{2} - b^{2}

a = sec (x), b = tan (x)

= sec^{2} (x) - tan^{2} (x)

= sec^{2} (x) - tan^{2} (x)

피타고라스 정체성 사용:

sec^{2} (x) = tan^{2} (x) + 1

sec^{2} (x) - tan^{2} (x) = 1

= 1

= 1 \cdot (sec^{2} (x) + tan^{2} (x) + sec (x) tan (x)) (sec^{2} (x) + tan^{2} (x) - sec (x) tan (x))

1 \cdot (sec^{2} (x) + tan^{2} (x) + sec (x) tan (x)) (sec^{2} (x) + tan^{2} (x) - sec (x) tan (x))

단순화하세요:

(sec^{2} (x) + tan^{2} (x) + sec (x) tan (x)) (sec^{2} (x) + tan^{2} (x) - sec (x) tan (x))

1 \cdot (sec^{2} (x) + tan^{2} (x) + sec (x) tan (x)) (sec^{2} (x) + tan^{2} (x) - sec (x) tan (x))

곱하다:

1 \cdot (sec^{2} (x) + tan^{2} (x) + sec (x) tan (x)) = (sec^{2} (x) + tan^{2} (x) + sec (x) tan (x))

= (sec^{2} (x) + tan^{2} (x) + sec (x) tan (x)) (sec^{2} (x) + tan^{2} (x) - sec (x) tan (x))

= (sec^{2} (x) + tan^{2} (x) + sec (x) tan (x)) (sec^{2} (x) + tan^{2} (x) - sec (x) tan (x))

(sec^{2} (x) + tan^{2} (x) + sec (x) tan (x)) (sec^{2} (x) + tan^{2} (x) - sec (x) tan (x)) = 0

각 부분을 개별적으로 해결

sec^{2} (x) + tan^{2} (x) + sec (x) tan (x) = 0 or sec^{2} (x) + tan^{2} (x) - sec (x) tan (x) = 0

sec^{2} (x) + tan^{2} (x) + sec (x) tan (x) = 0 :

해결책 없음

sec^{2} (x) + tan^{2} (x) + sec (x) tan (x) = 0

죄로 표현하라, 왜냐하면

sec^{2} (x) + tan^{2} (x) + sec (x) tan (x)

기본 삼각형 항등식 사용:

sec (x) = \frac{1}{cos ( x )}

= (\frac{1}{cos ( x )})^{2} + tan^{2} (x) + \frac{1}{cos ( x )} tan (x)

기본 삼각형 항등식 사용:

tan (x) = \frac{sin ( x )}{cos ( x )}

= (\frac{1}{cos ( x )})^{2} + (\frac{sin ( x )}{cos ( x )})^{2} + \frac{1}{cos ( x )} \cdot \frac{sin ( x )}{cos ( x )}

(\frac{1}{cos ( x )})^{2} + (\frac{sin ( x )}{cos ( x )})^{2} + \frac{1}{cos ( x )} \cdot \frac{sin ( x )}{cos ( x )}

단순화하세요:

\frac{1 + sin ^{2} ( x ) + sin ( x )}{cos ^{2} ( x )}

(\frac{1}{cos ( x )})^{2} + (\frac{sin ( x )}{cos ( x )})^{2} + \frac{1}{cos ( x )} \cdot \frac{sin ( x )}{cos ( x )}

(\frac{1}{cos ( x )})^{2} = \frac{1}{cos ^{2} ( x )}

(\frac{1}{cos ( x )})^{2}

지수 규칙 적용:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{cos ^{2} ( x )}

규칙 적용

1^{a} = 1

1^{2} = 1

= \frac{1}{cos ^{2} ( x )}

(\frac{sin ( x )}{cos ( x )})^{2} = \frac{sin ^{2} ( x )}{cos ^{2} ( x )}

(\frac{sin ( x )}{cos ( x )})^{2}

지수 규칙 적용:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{sin ^{2} ( x )}{cos ^{2} ( x )}

\frac{1}{cos ( x )} \cdot \frac{sin ( x )}{cos ( x )} = \frac{sin ( x )}{cos ^{2} ( x )}

\frac{1}{cos ( x )} \cdot \frac{sin ( x )}{cos ( x )}

다중 분수:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot sin ( x )}{cos ( x ) cos ( x )}

곱하다:

1 \cdot sin (x) = sin (x)

= \frac{sin ( x )}{cos ( x ) cos ( x )}

cos (x) cos (x) = cos^{2} (x)

cos (x) cos (x)

지수 규칙 적용:

a^{b} \cdot a^{c} = a^{b + c}

cos (x) cos (x) = cos^{1 + 1} (x)

= cos^{1 + 1} (x)

숫자 추가:

1 + 1 = 2

= cos^{2} (x)

= \frac{sin ( x )}{cos ^{2} ( x )}

= \frac{1}{cos ^{2} ( x )} + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} + \frac{sin ( x )}{cos ^{2} ( x )}

규칙 적용

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + sin ^{2} ( x ) + sin ( x )}{cos ^{2} ( x )}

= \frac{1 + sin ^{2} ( x ) + sin ( x )}{cos ^{2} ( x )}

\frac{1 + sin ( x ) + sin ^{2} ( x )}{cos ^{2} ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

1 + sin (x) + sin^{2} (x) = 0

대체로 해결

1 + sin (x) + sin^{2} (x) = 0

하게:

sin (x) = u

1 + u + u^{2} = 0

1 + u + u^{2} = 0 : u = - \frac{1}{2} + i \frac{3}{2}, u = - \frac{1}{2} - i \frac{3}{2}

1 + u + u^{2} = 0

표준 양식으로 작성

a x^{2} + b x + c = 0

u^{2} + u + 1 = 0

쿼드 공식으로 해결

u^{2} + u + 1 = 0

4차 방정식 공식:

위해서

a = 1, b = 1, c = 1

u_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

u_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot 1

단순화하세요:

3 i

1^{2} - 4 \cdot 1 \cdot 1

규칙 적용

1^{a} = 1

1^{2} = 1

= 1 - 4 \cdot 1 \cdot 1

숫자를 곱하시오:

4 \cdot 1 \cdot 1 = 4

= 1 - 4

숫자를 빼세요:

1 - 4 = - 3

= - 3

급진적인 규칙 적용:

- a = - 1 a

- 3 = - 1 3

= - 1 3

허수 규칙 적용:

- 1 = i

= 3 i

u_{1, 2} = \frac{- 1 \pm 3 i}{2 \cdot 1}

솔루션 분리

u_{1} = \frac{- 1 + 3 i}{2 \cdot 1}, u_{2} = \frac{- 1 - 3 i}{2 \cdot 1}

u = \frac{- 1 + 3 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{3}{2}

\frac{- 1 + 3 i}{2 \cdot 1}

숫자를 곱하시오:

2 \cdot 1 = 2

= \frac{- 1 + 3 i}{2}

다시 쓰다

\frac{- 1 + 3 i}{2}

표준복합형태로:

- \frac{1}{2} + \frac{3}{2} i

\frac{- 1 + 3 i}{2}

분수 규칙 적용:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 1 + 3 i}{2} = - \frac{1}{2} + \frac{3 i}{2}

= - \frac{1}{2} + \frac{3 i}{2}

= - \frac{1}{2} + \frac{3}{2} i

u = \frac{- 1 - 3 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{3}{2}

\frac{- 1 - 3 i}{2 \cdot 1}

숫자를 곱하시오:

2 \cdot 1 = 2

= \frac{- 1 - 3 i}{2}

다시 쓰다

\frac{- 1 - 3 i}{2}

표준복합형태로:

- \frac{1}{2} - \frac{3}{2} i

\frac{- 1 - 3 i}{2}

분수 규칙 적용:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 1 - 3 i}{2} = - \frac{1}{2} - \frac{3 i}{2}

= - \frac{1}{2} - \frac{3 i}{2}

= - \frac{1}{2} - \frac{3}{2} i

2차 방정식의 해는 다음과 같다:

u = - \frac{1}{2} + i \frac{3}{2}, u = - \frac{1}{2} - i \frac{3}{2}

뒤로 대체

u = sin (x)

sin (x) = - \frac{1}{2} + i \frac{3}{2}, sin (x) = - \frac{1}{2} - i \frac{3}{2}

sin (x) = - \frac{1}{2} + i \frac{3}{2}, sin (x) = - \frac{1}{2} - i \frac{3}{2}

sin (x) = - \frac{1}{2} + i \frac{3}{2} :

해결책 없음

sin (x) = - \frac{1}{2} + i \frac{3}{2}

해결책 없음

sin (x) = - \frac{1}{2} - i \frac{3}{2} :

해결책 없음

sin (x) = - \frac{1}{2} - i \frac{3}{2}

해결책 없음

모든 솔루션 결합

해결책 없음

sec^{2} (x) + tan^{2} (x) - sec (x) tan (x) = 0 :

해결책 없음

sec^{2} (x) + tan^{2} (x) - sec (x) tan (x) = 0

죄로 표현하라, 왜냐하면

sec^{2} (x) + tan^{2} (x) - sec (x) tan (x)

기본 삼각형 항등식 사용:

sec (x) = \frac{1}{cos ( x )}

= (\frac{1}{cos ( x )})^{2} + tan^{2} (x) - \frac{1}{cos ( x )} tan (x)

기본 삼각형 항등식 사용:

tan (x) = \frac{sin ( x )}{cos ( x )}

= (\frac{1}{cos ( x )})^{2} + (\frac{sin ( x )}{cos ( x )})^{2} - \frac{1}{cos ( x )} \cdot \frac{sin ( x )}{cos ( x )}

(\frac{1}{cos ( x )})^{2} + (\frac{sin ( x )}{cos ( x )})^{2} - \frac{1}{cos ( x )} \cdot \frac{sin ( x )}{cos ( x )}

단순화하세요:

\frac{1 + sin ^{2} ( x ) - sin ( x )}{cos ^{2} ( x )}

(\frac{1}{cos ( x )})^{2} + (\frac{sin ( x )}{cos ( x )})^{2} - \frac{1}{cos ( x )} \cdot \frac{sin ( x )}{cos ( x )}

(\frac{1}{cos ( x )})^{2} = \frac{1}{cos ^{2} ( x )}

(\frac{1}{cos ( x )})^{2}

지수 규칙 적용:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{cos ^{2} ( x )}

규칙 적용

1^{a} = 1

1^{2} = 1

= \frac{1}{cos ^{2} ( x )}

(\frac{sin ( x )}{cos ( x )})^{2} = \frac{sin ^{2} ( x )}{cos ^{2} ( x )}

(\frac{sin ( x )}{cos ( x )})^{2}

지수 규칙 적용:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{sin ^{2} ( x )}{cos ^{2} ( x )}

\frac{1}{cos ( x )} \cdot \frac{sin ( x )}{cos ( x )} = \frac{sin ( x )}{cos ^{2} ( x )}

\frac{1}{cos ( x )} \cdot \frac{sin ( x )}{cos ( x )}

다중 분수:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot sin ( x )}{cos ( x ) cos ( x )}

곱하다:

1 \cdot sin (x) = sin (x)

= \frac{sin ( x )}{cos ( x ) cos ( x )}

cos (x) cos (x) = cos^{2} (x)

cos (x) cos (x)

지수 규칙 적용:

a^{b} \cdot a^{c} = a^{b + c}

cos (x) cos (x) = cos^{1 + 1} (x)

= cos^{1 + 1} (x)

숫자 추가:

1 + 1 = 2

= cos^{2} (x)

= \frac{sin ( x )}{cos ^{2} ( x )}

= \frac{1}{cos ^{2} ( x )} + \frac{sin ^{2} ( x )}{cos ^{2} ( x )} - \frac{sin ( x )}{cos ^{2} ( x )}

규칙 적용

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + sin ^{2} ( x ) - sin ( x )}{cos ^{2} ( x )}

= \frac{1 + sin ^{2} ( x ) - sin ( x )}{cos ^{2} ( x )}

\frac{1 - sin ( x ) + sin ^{2} ( x )}{cos ^{2} ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

1 - sin (x) + sin^{2} (x) = 0

대체로 해결

1 - sin (x) + sin^{2} (x) = 0

하게:

sin (x) = u

1 - u + u^{2} = 0

1 - u + u^{2} = 0 : u = \frac{1}{2} + i \frac{3}{2}, u = \frac{1}{2} - i \frac{3}{2}

1 - u + u^{2} = 0

표준 양식으로 작성

a x^{2} + b x + c = 0

u^{2} - u + 1 = 0

쿼드 공식으로 해결

u^{2} - u + 1 = 0

4차 방정식 공식:

위해서

a = 1, b = - 1, c = 1

u_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

u_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 1

단순화하세요:

3 i

(- 1)^{2} - 4 \cdot 1 \cdot 1

(- 1)^{2} = 1

(- 1)^{2}

지수 규칙 적용:

(- a)^{n} = a^{n},

이면

n

균등하다

(- 1)^{2} = 1^{2}

= 1^{2}

규칙 적용

1^{a} = 1

= 1

4 \cdot 1 \cdot 1 = 4

4 \cdot 1 \cdot 1

숫자를 곱하시오:

4 \cdot 1 \cdot 1 = 4

= 4

= 1 - 4

숫자를 빼세요:

1 - 4 = - 3

= - 3

급진적인 규칙 적용:

- a = - 1 a

- 3 = - 1 3

= - 1 3

허수 규칙 적용:

- 1 = i

= 3 i

u_{1, 2} = \frac{- ( - 1 ) \pm 3 i}{2 \cdot 1}

솔루션 분리

u_{1} = \frac{- ( - 1 ) + 3 i}{2 \cdot 1}, u_{2} = \frac{- ( - 1 ) - 3 i}{2 \cdot 1}

u = \frac{- ( - 1 ) + 3 i}{2 \cdot 1} : \frac{1}{2} + i \frac{3}{2}

\frac{- ( - 1 ) + 3 i}{2 \cdot 1}

규칙 적용

- (- a) = a

= \frac{1 + 3 i}{2 \cdot 1}

숫자를 곱하시오:

2 \cdot 1 = 2

= \frac{1 + 3 i}{2}

다시 쓰다

\frac{1 + 3 i}{2}

표준복합형태로:

\frac{1}{2} + \frac{3}{2} i

\frac{1 + 3 i}{2}

분수 규칙 적용:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 + 3 i}{2} = \frac{1}{2} + \frac{3 i}{2}

= \frac{1}{2} + \frac{3 i}{2}

= \frac{1}{2} + \frac{3}{2} i

u = \frac{- ( - 1 ) - 3 i}{2 \cdot 1} : \frac{1}{2} - i \frac{3}{2}

\frac{- ( - 1 ) - 3 i}{2 \cdot 1}

규칙 적용

- (- a) = a

= \frac{1 - 3 i}{2 \cdot 1}

숫자를 곱하시오:

2 \cdot 1 = 2

= \frac{1 - 3 i}{2}

다시 쓰다

\frac{1 - 3 i}{2}

표준복합형태로:

\frac{1}{2} - \frac{3}{2} i

\frac{1 - 3 i}{2}

분수 규칙 적용:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 - 3 i}{2} = \frac{1}{2} - \frac{3 i}{2}

= \frac{1}{2} - \frac{3 i}{2}

= \frac{1}{2} - \frac{3}{2} i

2차 방정식의 해는 다음과 같다:

u = \frac{1}{2} + i \frac{3}{2}, u = \frac{1}{2} - i \frac{3}{2}

뒤로 대체

u = sin (x)

sin (x) = \frac{1}{2} + i \frac{3}{2}, sin (x) = \frac{1}{2} - i \frac{3}{2}

sin (x) = \frac{1}{2} + i \frac{3}{2}, sin (x) = \frac{1}{2} - i \frac{3}{2}

sin (x) = \frac{1}{2} + i \frac{3}{2} :

해결책 없음

sin (x) = \frac{1}{2} + i \frac{3}{2}

해결책 없음

sin (x) = \frac{1}{2} - i \frac{3}{2} :

해결책 없음

sin (x) = \frac{1}{2} - i \frac{3}{2}

해결책 없음

모든 솔루션 결합

해결책 없음

모든 솔루션 결합

솔루션 없음 x \in R

그래프

인기 있는 예

cos^2(2x)-2sin^2(x)-1=0

cos^{2} (2 x) - 2 sin^{2} (x) - 1 = 0

cos^2(x)+2=sin(x)

cos^{2} (x) + 2 = sin (x)

-sin(2x)-3cos(x)=0

- sin (2 x) - 3 cos (x) = 0

solvefor x,y=3cos(fxx+pi/2)+5

so l v e f or x, y = 3 cos (f xx + \frac{π}{2}) + 5

sin(x)cos(x)=sin(x),0<x<= 2pi

sin (x) cos (x) = sin (x), 0 < x \leq 2 π