sin(x)= pi/4+(0pi)/2

Lösung

sin (x) = \frac{π}{4} + \frac{0 π}{2}

x = 0.90333 \dots + 2 πn, x = π - 0.90333 \dots + 2 πn

Radianten

x = 0.90333 \dots + 6.28318 \dots n, x = π - 0.90333 \dots + 6.28318 \dots n

Schritte zur Lösung

sin (x) = \frac{π}{4} + \frac{0 π}{2}

Vereinfache

\frac{π}{4} + \frac{0 π}{2} : \frac{π}{4}

\frac{π}{4} + \frac{0 π}{2}

\frac{0 π}{2} = 0

\frac{0 π}{2}

Wende Regel an

0 \cdot a = 0

= \frac{0}{2}

Wende Regel an

\frac{0}{a} = 0, a \neq = 0

= 0

= \frac{π}{4} + 0

\frac{π}{4} + 0 = \frac{π}{4}

= \frac{π}{4}

Wende die Eigenschaften der Trigonometrie an

sin (x) = \frac{π}{4}

Allgemeine Lösung für

sin (x) = \frac{π}{4}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (\frac{π}{4}) + 2 πn, x = π - arcsin (\frac{π}{4}) + 2 πn

x = arcsin (\frac{π}{4}) + 2 πn, x = π - arcsin (\frac{π}{4}) + 2 πn

Zeige Lösungen in Dezimalform

x = 0.90333 \dots + 2 πn, x = π - 0.90333 \dots + 2 πn

cos (2 x) - sin (x) - 1 = 0

cos (x) = \frac{5}{20}

sin (x) - 3 cos (x) = 1, 0 \leq x \leq 2 π

arccos (θ) = \frac{5}{7}

cos (θ) = \frac{- 139}{160}