English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popolare Trigonometria >

cos(pi/x)=(sqrt(3))/3

Soluzione

cos (\frac{π}{x}) = \frac{3}{3}

Soluzione

x = \frac{π}{0.95531 \dots + 2 πn}, x = \frac{π}{2 π - 0.95531 \dots + 2 πn}

Gradi

x = 0^{\circ} + 24.86702 \dots^{\circ} n, x = 0^{\circ} + 15.50246 \dots^{\circ} n

Fasi della soluzione

cos (\frac{π}{x}) = \frac{3}{3}

Applica le proprietà inverse delle funzioni trigonometriche

cos (\frac{π}{x}) = \frac{3}{3}

Soluzioni generali per

cos (\frac{π}{x}) = \frac{3}{3}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

\frac{π}{x} = arccos (\frac{3}{3}) + 2 πn, \frac{π}{x} = 2 π - arccos (\frac{3}{3}) + 2 πn

\frac{π}{x} = arccos (\frac{3}{3}) + 2 πn, \frac{π}{x} = 2 π - arccos (\frac{3}{3}) + 2 πn

Risolvi

\frac{π}{x} = arccos (\frac{3}{3}) + 2 πn : x = \frac{π}{arccos ( \frac{1}{3} ) + 2 πn}; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

\frac{π}{x} = arccos (\frac{3}{3}) + 2 πn

Moltiplica entrambi i lati per

x

\frac{π}{x} = arccos (\frac{3}{3}) + 2 πn

Moltiplica entrambi i lati per

x

\frac{π}{x} x = arccos (\frac{3}{3}) x + 2 πn x

Semplificare

π = arccos (\frac{3}{3}) x + 2 πn x

π = arccos (\frac{3}{3}) x + 2 πn x

Scambia i lati

arccos (\frac{3}{3}) x + 2 πn x = π

Semplificare

arccos (\frac{3}{3}) x + 2 πn x : arccos (\frac{1}{3}) x + 2 πn x

arccos (\frac{3}{3}) x + 2 πn x

\frac{3}{3} = \frac{1}{3}

\frac{3}{3}

Applicare la regola della radice:

n a = a^{\frac{1}{n}}

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}}}{3}

Applica la regola degli esponenti:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{1}{3 ^{1 - \frac{1}{2}}}

Sottrai i numeri:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{1}{3 ^{\frac{1}{2}}}

Applicare la regola della radice:

a^{\frac{1}{n}} = n a

3^{\frac{1}{2}} = 3

= \frac{1}{3}

= arccos (\frac{1}{3}) x + 2 πn x

arccos (\frac{1}{3}) x + 2 πn x = π

arccos (\frac{3}{3}) x + 2 πn x = π

Fattorizza

arccos (\frac{3}{3}) x + 2 πn x : x (arccos (\frac{1}{3}) + 2 πn)

arccos (\frac{3}{3}) x + 2 πn x

Fattorizzare dal termine comune

x

= x (arccos (\frac{3}{3}) + 2 πn)

\frac{3}{3} = \frac{1}{3}

\frac{3}{3}

Applicare la regola della radice:

n a = a^{\frac{1}{n}}

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}}}{3}

Applica la regola degli esponenti:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{1}{3 ^{1 - \frac{1}{2}}}

Sottrai i numeri:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{1}{3 ^{\frac{1}{2}}}

Applicare la regola della radice:

a^{\frac{1}{n}} = n a

3^{\frac{1}{2}} = 3

= \frac{1}{3}

= x (2 πn + arccos (\frac{1}{3}))

x (arccos (\frac{1}{3}) + 2 πn) = π

Dividere entrambi i lati per

arccos (\frac{1}{3}) + 2 πn; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

x (arccos (\frac{1}{3}) + 2 πn) = π

Dividere entrambi i lati per

arccos (\frac{1}{3}) + 2 πn; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

\frac{x ( arccos ( \frac{1}{3} ) + 2 πn )}{arccos ( \frac{1}{3} ) + 2 πn} = \frac{π}{arccos ( \frac{1}{3} ) + 2 πn}; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

Semplificare

\frac{x ( arccos ( \frac{1}{3} ) + 2 πn )}{arccos ( \frac{1}{3} ) + 2 πn} = \frac{π}{arccos ( \frac{1}{3} ) + 2 πn}

Semplificare

\frac{x ( arccos ( \frac{1}{3} ) + 2 πn )}{arccos ( \frac{1}{3} ) + 2 πn} : x

\frac{x ( arccos ( \frac{1}{3} ) + 2 πn )}{arccos ( \frac{1}{3} ) + 2 πn}

x (arccos (\frac{1}{3}) + 2 πn) = x (arccos (\frac{3}{3}) + 2 πn)

x (arccos (\frac{1}{3}) + 2 πn)

= x (2 πn + arccos (\frac{3}{3}))

= \frac{x ( 2 πn + arccos ( \frac{3}{3} ) )}{arccos ( \frac{1}{3} ) + 2 πn}

arccos (\frac{1}{3}) + 2 πn = arccos (\frac{3}{3}) + 2 πn

arccos (\frac{1}{3}) + 2 πn

= arccos (\frac{3}{3}) + 2 πn

= \frac{x ( 2 πn + arccos ( \frac{3}{3} ) )}{arccos ( \frac{3}{3} ) + 2 πn}

Cancella il fattore comune:

arccos (\frac{3}{3}) + 2 πn

= x

Semplificare

\frac{π}{arccos ( \frac{1}{3} ) + 2 πn} : \frac{π}{arccos ( \frac{3}{3} ) + 2 πn}

\frac{π}{arccos ( \frac{1}{3} ) + 2 πn}

arccos (\frac{1}{3}) + 2 πn = arccos (\frac{3}{3}) + 2 πn

arccos (\frac{1}{3}) + 2 πn

= arccos (\frac{3}{3}) + 2 πn

= \frac{π}{arccos ( \frac{3}{3} ) + 2 πn}

x = \frac{π}{arccos ( \frac{3}{3} ) + 2 πn}; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

x = \frac{π}{arccos ( \frac{3}{3} ) + 2 πn}; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

x = \frac{π}{arccos ( \frac{3}{3} ) + 2 πn}; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

Semplificare

\frac{π}{arccos ( \frac{3}{3} ) + 2 πn} : \frac{π}{arccos ( \frac{1}{3} ) + 2 πn}

\frac{π}{arccos ( \frac{3}{3} ) + 2 πn}

\frac{3}{3} = \frac{1}{3}

\frac{3}{3}

Applicare la regola della radice:

n a = a^{\frac{1}{n}}

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}}}{3}

Applica la regola degli esponenti:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{1}{3 ^{1 - \frac{1}{2}}}

Sottrai i numeri:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{1}{3 ^{\frac{1}{2}}}

Applicare la regola della radice:

a^{\frac{1}{n}} = n a

3^{\frac{1}{2}} = 3

= \frac{1}{3}

= \frac{π}{arccos ( \frac{1}{3} ) + 2 πn}

x = \frac{π}{arccos ( \frac{1}{3} ) + 2 πn}; n \neq = - \frac{arccos ( \frac{1}{3} )}{2 π}

Risolvi

\frac{π}{x} = 2 π - arccos (\frac{3}{3}) + 2 πn : x = \frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

\frac{π}{x} = 2 π - arccos (\frac{3}{3}) + 2 πn

Moltiplica entrambi i lati per

x

\frac{π}{x} = 2 π - arccos (\frac{3}{3}) + 2 πn

Moltiplica entrambi i lati per

x

\frac{π}{x} x = 2 π x - arccos (\frac{3}{3}) x + 2 πn x

Semplificare

π = 2 π x - arccos (\frac{3}{3}) x + 2 πn x

π = 2 π x - arccos (\frac{3}{3}) x + 2 πn x

Scambia i lati

2 π x - arccos (\frac{3}{3}) x + 2 πn x = π

Semplificare

2 π x - arccos (\frac{3}{3}) x + 2 πn x : 2 π x - arccos (\frac{1}{3}) x + 2 πn x

2 π x - arccos (\frac{3}{3}) x + 2 πn x

\frac{3}{3} = \frac{1}{3}

\frac{3}{3}

Applicare la regola della radice:

n a = a^{\frac{1}{n}}

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}}}{3}

Applica la regola degli esponenti:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{1}{3 ^{1 - \frac{1}{2}}}

Sottrai i numeri:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{1}{3 ^{\frac{1}{2}}}

Applicare la regola della radice:

a^{\frac{1}{n}} = n a

3^{\frac{1}{2}} = 3

= \frac{1}{3}

= 2 π x - arccos (\frac{1}{3}) x + 2 πn x

2 π x - arccos (\frac{1}{3}) x + 2 πn x = π

2 π x - arccos (\frac{3}{3}) x + 2 πn x = π

Fattorizza

2 π x - arccos (\frac{3}{3}) x + 2 πn x : x (2 π - arccos (\frac{1}{3}) + 2 πn)

2 π x - arccos (\frac{3}{3}) x + 2 πn x

Fattorizzare dal termine comune

x

= x (2 π - arccos (\frac{3}{3}) + 2 πn)

\frac{3}{3} = \frac{1}{3}

\frac{3}{3}

Applicare la regola della radice:

n a = a^{\frac{1}{n}}

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}}}{3}

Applica la regola degli esponenti:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{1}{3 ^{1 - \frac{1}{2}}}

Sottrai i numeri:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{1}{3 ^{\frac{1}{2}}}

Applicare la regola della radice:

a^{\frac{1}{n}} = n a

3^{\frac{1}{2}} = 3

= \frac{1}{3}

= x (2 π + 2 πn - arccos (\frac{1}{3}))

x (2 π - arccos (\frac{1}{3}) + 2 πn) = π

Dividere entrambi i lati per

2 π - arccos (\frac{1}{3}) + 2 πn; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

x (2 π - arccos (\frac{1}{3}) + 2 πn) = π

Dividere entrambi i lati per

2 π - arccos (\frac{1}{3}) + 2 πn; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

\frac{x ( 2 π - arccos ( \frac{1}{3} ) + 2 πn )}{2 π - arccos ( \frac{1}{3} ) + 2 πn} = \frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

Semplificare

\frac{x ( 2 π - arccos ( \frac{1}{3} ) + 2 πn )}{2 π - arccos ( \frac{1}{3} ) + 2 πn} = \frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

Semplificare

\frac{x ( 2 π - arccos ( \frac{1}{3} ) + 2 πn )}{2 π - arccos ( \frac{1}{3} ) + 2 πn} : x

\frac{x ( 2 π - arccos ( \frac{1}{3} ) + 2 πn )}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

x (2 π - arccos (\frac{1}{3}) + 2 πn) = x (2 π - arccos (\frac{3}{3}) + 2 πn)

x (2 π - arccos (\frac{1}{3}) + 2 πn)

= x (2 π + 2 πn - arccos (\frac{3}{3}))

= \frac{x ( 2 π + 2 πn - arccos ( \frac{3}{3} ) )}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

2 π - arccos (\frac{1}{3}) + 2 πn = 2 π - arccos (\frac{3}{3}) + 2 πn

2 π - arccos (\frac{1}{3}) + 2 πn

= 2 π - arccos (\frac{3}{3}) + 2 πn

= \frac{x ( 2 π + 2 πn - arccos ( \frac{3}{3} ) )}{2 π - arccos ( \frac{3}{3} ) + 2 πn}

Cancella il fattore comune:

2 π - arccos (\frac{3}{3}) + 2 πn

= x

Semplificare

\frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn} : \frac{π}{2 π - arccos ( \frac{3}{3} ) + 2 πn}

\frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

2 π - arccos (\frac{1}{3}) + 2 πn = 2 π - arccos (\frac{3}{3}) + 2 πn

2 π - arccos (\frac{1}{3}) + 2 πn

= 2 π - arccos (\frac{3}{3}) + 2 πn

= \frac{π}{2 π - arccos ( \frac{3}{3} ) + 2 πn}

x = \frac{π}{2 π - arccos ( \frac{3}{3} ) + 2 πn}; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

x = \frac{π}{2 π - arccos ( \frac{3}{3} ) + 2 πn}; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

x = \frac{π}{2 π - arccos ( \frac{3}{3} ) + 2 πn}; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

Semplificare

\frac{π}{2 π - arccos ( \frac{3}{3} ) + 2 πn} : \frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

\frac{π}{2 π - arccos ( \frac{3}{3} ) + 2 πn}

\frac{3}{3} = \frac{1}{3}

\frac{3}{3}

Applicare la regola della radice:

n a = a^{\frac{1}{n}}

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}}}{3}

Applica la regola degli esponenti:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{1}{3 ^{1 - \frac{1}{2}}}

Sottrai i numeri:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{1}{3 ^{\frac{1}{2}}}

Applicare la regola della radice:

a^{\frac{1}{n}} = n a

3^{\frac{1}{2}} = 3

= \frac{1}{3}

= \frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

x = \frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}; n \neq = \frac{- 2 π + arccos ( \frac{1}{3} )}{2 π}

x = \frac{π}{arccos ( \frac{1}{3} ) + 2 πn}, x = \frac{π}{2 π - arccos ( \frac{1}{3} ) + 2 πn}

Mostra le soluzioni in forma decimale

x = \frac{π}{0.95531 \dots + 2 πn}, x = \frac{π}{2 π - 0.95531 \dots + 2 πn}

Grafico

Esempi popolari

solvefor y,arctan(y/x)=ln(x)

so l v e f or y, arctan (\frac{y}{x}) = ln (x)

sin(x)=50

sin (x) = 50

58.2^2=25.8^2+33.4^2-2(25.8(33.4))cos(a)

58. 2^{2} = 25. 8^{2} + 33. 4^{2} - 2 (25.8 (33.4)) cos (a)

4cos(θ)-1=2sin(θ)tan(θ)

4 cos (θ) - 1 = 2 sin (θ) tan (θ)

3tan(θ)=tan(2θ)

3 tan (θ) = tan (2 θ)